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melomori [17]
3 years ago
8

Marsha has budgeted no more than $3,000 on centerpieces for the tables at the reception, which inequality represents all possibl

e combinations of x, the number of Guest Tables Lily Arrangements, and y, the number of Family Table Rose Arrangements, that Marsha can buy for no more than $3,000
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
8 0

Answer:

x+y\leq 3000

Step-by-step explanation:

Given : Marsha has budgeted no more than $3,000 on centerpieces for the tables

x denotes the number of Guest Tables Lily Arrangements

y denotes the number of Family Table Rose Arrangements

To Find: Which inequality represents all possible combinations of x,  and y,  that Marsha can buy for no more than $3,000?

Solution :

Since there are x number of Guest Tables Lily Arrangements.

And there are y  number of Family Table Rose Arrangements

Since she cannot spend more than 3000 on centerpieces .

So, the inequality becomes:

x+y\leq 3000

Hence inequality represents all possible combinations of x and y that Marsha can buy for no more than $3,000:

x+y\leq 3000

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aleksandrvk [35]

Answer: Choice B

(6\sqrt{5}+5)i

==========================================================

Work Shown:

\sqrt{-5}+\sqrt{-25}+\sqrt{-125}\\\\\sqrt{-1*5}+\sqrt{-1*25}+\sqrt{-1*25*5}\\\\\sqrt{-1}*\sqrt{5}+\sqrt{-1}*\sqrt{25}+\sqrt{-1}*\sqrt{25}*\sqrt{5}\\\\i*\sqrt{5}+i*5+i*5*\sqrt{5}\\\\i*\sqrt{5}+5i+5i*\sqrt{5}\\\\(i\sqrt{5}+5i*\sqrt{5})+5i\\\\(\sqrt{5}+5\sqrt{5})i+5i\\\\(6\sqrt{5})i+5i\\\\(6\sqrt{5}+5)i\\\\

This points us to answer choice B

7 0
3 years ago
The number of students attending summer school at a local community college has been decreasing each year by 7%. If 847 students
alina1380 [7]

Answer:

≈ 634

Step-by-step explanation:

n = 847(1 * .07)^4

n = 847(0.93)^4

n = 633.60005247

n ≈ 634

3 0
3 years ago
I need help with #11
Troyanec [42]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template in mind, let's take a peek at this function

\bf \begin{array}{lllcclll}
y=&2(&1x&-2)^2&-4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\
\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\
D=-4\impliedby \textit{vertical down shift of 4 units}

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically
8 0
3 years ago
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den301095 [7]

Answer: 28 ft

Step-by-step explanation:

Multiply 3,4, and 7 to get 84 ft cubed. To find the volume of a pyramid, divide by 3 to get 28 ft.

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Answer:

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πr^2

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