Selena played 32 games of chess. If she won x games, which expression represents her losses?

Mathematics

2 answers:

katrin [286]2 years ago

6 0

<span>Selena played 32 games of chess

won = x
lost = (total - won) = 32 - x

Answer is C
</span>

melamori03 [73]2 years ago

4 0

The answer is ........ (C)

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F(x)=6x^2 +10x−1

KATRIN_1 [288]

Answer: It has two distinct real zeros.

Step-by-step explanation:

The formula that is used to calculate the discriminant of a Quadratic function is the one shown below:

$D=b^2-4ac$

In this case you have the following Quadractic function provided in the exercise:

$f(x)=6x^2 +10x-1$

Let's make it equal to 0:

$0=6x^2 +10x-1$

You can identify that:

$a=6\\\\b=10$

Knowing these values, you can substitute them into the formula and then evaluate:

$D=10^2-4(6)(-1)\\\\D=124$

Therefore, since:

$D>0$

You can determine that the it has two distinct real roots.

3 0

3 years ago

Write the slope-intercept form of the equation of the line satisfying the given conditions through(3,-3); slope=-4

il63 [147K]

Answer:

y=-4x+9

Step-by-step explanation:

y-y1=m(x-x1)

y-(-3)=-4(x-3)

y+3=-4(x-3)

y=-4x+12-3

y=-4x+9

7 0

3 years ago

Question 12<br> With steps please

34kurt

$Answer:\ \boxed{5^2}$

$\sqrt[n]{a}=a^\frac{1}{n}\\\\\text{therefore}\\\\\sqrt5=5^\frac{1}{2}\\----------------\\25=5^2\\----------------\\78,125=5^7\\----------------\\\text{use}\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\----------------\\\\\dfrac{\sqrt5\times78,125}{25\times5^{\frac{7}{2}}}=\dfrac{5^\frac{1}{2}\times5^7}{5^2\times5^\frac{7}{2}}=\dfrac{5^{\frac{1}{2}+7}}{5^{2+3\frac{1}{2}}}=\dfrac{5^{7\frac{1}{2}}}{5^{5\frac{1}{2}}}=5^{7\frac{1}{2}-5\frac{1}{2}}=\boxed{5^2}$