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Gnoma [55]
3 years ago
12

What is the aim of golden rain demonstration​

Chemistry
1 answer:
Andrei [34K]3 years ago
3 0

demonstrates the formation of a solid precipitate

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3. 2.15 x 3.1 x 100 =
jeka94

Answer:

666.5

Explanation:

Multiply 2.15 and 3.1 to get 6.665.

6.665×100≈666.5

Multiply 6.665 and 100 to get 666.5.

666.5

3 0
3 years ago
Read 2 more answers
Which of he following compounds is always part of an aqueous solution
weqwewe [10]

Answer: Water because if we say aqueous it means it resembles water or related to water.

7 0
3 years ago
A certain water tower hold 4.6×10^5 gallons of water. find the volume of that water in liters.​
Readme [11.4K]

Answer: 1741289L

Explanation:

1 gallon = 3.78541 L

4.6×10^5 gallons = 4.6×10^5 x 3.78541 = 1741289L

6 0
3 years ago
Read 2 more answers
How many moles of dinitrogen monoxide are present in 9.3 x 10^22 molecules of this compound?
Step2247 [10]

Answer:

<h2>0.15 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities.

From the question we have

n =  \frac{9.3 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.154485...

We have the final answer as

<h3>0.15 moles</h3>

Hope this helps you

8 0
3 years ago
Find the specific heat of an unknown material with an initial temperature of 20°C, when 5000 Joules are applied to a 50 gram sam
xxTIMURxx [149]

Answer:

2J/g°C

Explanation:

Q = 5000J

Initial temperature (T1) = 20°C

Final temperature (T2) = 70°C

Specific heat capacity (c) = ?

Heat energy (Q) = mc∇T

Q = mc∇T

Q = mc(T2 - T1)

5000 = 50 × c × (70 - 20)

5000 = 50c × 50

5000 = 2500c

c = 5000 / 2500

c = 2J/g°C

The specific heat capacity of the substance is 2J/g°C

8 0
3 years ago
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