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GarryVolchara [31]
3 years ago
5

How much heat would be evolved (released) if 50.0g of steam is at 114°C was cooled and condensed into water at 87°C?

Chemistry
1 answer:
LuckyWell [14K]3 years ago
6 0

Answer:

Q ≈ 1 x 10⁵ joules (1 sig. fig. based on 50g sample given)

Explanation:

Three heat transitions need be considered. Cooling the steam to 100°C, condensing the steam to water and cooling the water from 100°C to 87°C.

Total Heat exchange (Q) = ∑ heat transitions

Q = (m·c·ΔT)steam + (m·ΔH)condensation + (m·c·ΔT)water cooling

= (50g x 0.48j/g·°C x 14°C) + (50g x 2259j/g) + (50g x 4.184j/g·°C)

= 24j + 112,950j + 209.2j

= 113,183.2j ≈ 1 x 10⁵ joules (1 sig. fig. based on 50g sample given)

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Which two elements have the same number of energy levels with electrons in them?(1 point)
Vladimir79 [104]

Its B) Boron and Oxygen

5 0
3 years ago
What is the product when magnesium reacts with nitrogen? Mg(s) + N2(g) → Mg2N3(s) Mg3N(s) Mg3N2(s) MgN3(s)
bixtya [17]
Look at the periodic table to find the charge on atoms.
 Magnesium is +2 and Nitrogen is -3. Since there are two nitrogen charge 2*-3 = -6 there needs to be 3 Mg then (3*2+ = 6+) to pair with the two nitrogen.
3 Mg(+2) + 2 N(-3) = Mg3N2

6 0
3 years ago
Read 2 more answers
Five students performed a Kjeldahl nitrogen analysis of a protein sample. The following weight % nitrogen values were determined
Sunny_sXe [5.5K]

Answer:

G_calculated = 1.756

The outlier should be rejected, as G_cal > G_tab (= 1.463) at 95 % confidence.

Explanation:

The Grubb's test is used for identifying an outlier in data, which is from the same population. For this, a statistical term, G, is calculated for the suspected outlier. If the calculated value is greater than the tabulated G value then the suspected value is rejected. This term is given as,

G_calculated = | suspect value - mean| / s

Here,  suspect value is 13.8, mean is to be taken of all the data (including suspected value). s is the standard deviation of the sample data.

s is calculated from the following formula:

s = (Σ(xi - x)²/(N-1))^1/2

Here, x is the mean, which is 15.24, xi is individual value and N is the total number of data (5).

From the above formula, s is found to be

Standard Deviation, s = 0.820

Now for G value,

G_calculated = | 13.8 - 15.24| / (0.820)

G_ calculated = 1.756

The tabulated G value at 95 % confidence and N -1 (5 - 1 = 4) degree of freedom is, 1.463.

As calculated G (1.756) is greater than the tabulated G (1.463), the value 13.8 is considered an outlier at 95 % confidence.  

3 0
3 years ago
What is the volume of 1.56 kg of a compound whose molar mass is 81.86 g/mole and whose density is 41.2 g/ml?
hjlf

Answer:

v = 37.9 ml

Explanation:

Given data:

Mass of compound = 1.56 kg

Density = 41.2 g/ml

Volume of compound = ?

Solution:

First of all we will convert the mass into g.

1.56 ×1000 = 1560 g

Formula:

D=m/v

D= density

m=mass

V=volume

v = m/d

v =  1560 g / 41.2 g/ml

v = 37.9 ml

7 0
3 years ago
What is the mass of 8.8 x 10^22 of magnesium
Romashka-Z-Leto [24]

Answer:

0.05

moles

Explanation:

In a mole of any substance, there exist

6.02⋅1023

units of that substance.

So here, we got:

3.01⋅1022Mg atoms⋅1mol6.02⋅1023M gatoms=0.05mol

3 0
3 years ago
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