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GarryVolchara [31]
3 years ago
5

How much heat would be evolved (released) if 50.0g of steam is at 114°C was cooled and condensed into water at 87°C?

Chemistry
1 answer:
LuckyWell [14K]3 years ago
6 0

Answer:

Q ≈ 1 x 10⁵ joules (1 sig. fig. based on 50g sample given)

Explanation:

Three heat transitions need be considered. Cooling the steam to 100°C, condensing the steam to water and cooling the water from 100°C to 87°C.

Total Heat exchange (Q) = ∑ heat transitions

Q = (m·c·ΔT)steam + (m·ΔH)condensation + (m·c·ΔT)water cooling

= (50g x 0.48j/g·°C x 14°C) + (50g x 2259j/g) + (50g x 4.184j/g·°C)

= 24j + 112,950j + 209.2j

= 113,183.2j ≈ 1 x 10⁵ joules (1 sig. fig. based on 50g sample given)

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the reaction will shift towards the “heat”—shifts to the left

Explanation:

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Answer : The name of given unit cell is, FCC (face-centered cubic unit cell)

Explanation :

Unit cell : It is defined as the smallest 3-dimensional portion of a complete space lattice which when repeated over the and again in different directions produces the complete space lattice.

There are three types of unit cell.

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In SCC, the atoms are arranged at the corners.

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The number of atoms of unit cell = Z = 1

In BCC, the atoms are arranged at the corners and the body center.

Z=\frac{1}{8}\times 8+1=2

The number of atoms of unit cell = Z = 2

The given unit cell is, FCC because the atoms are arranged at the corners and the center of the 6 faces.

Z=\frac{1}{8}\times 8+\frac{1}{2}\times 6=4

The number of atoms of unit cell = Z = 4

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