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3 years ago

5

: The average student college loan rate is 4%. You borrowed $18,000 per year for 4 years for tuition, room, & board. If the

interest is computed as simple interest, annually, how much interest will you owe when you graduate. Assume 4 years interest on the freshman year loan, 3 years on the sophomore loan, 2 years on the junior loan, and 1 year on the senior loan.

1 answer:

gregori [183]3 years ago

7 0

Answer: A) 7,200

Step-by-step explanation:

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Find the volume of this cone.

Andrews [41]

Answer:

V = 180 ft^3

Step-by-step explanation:

The volume of a cone is found by

V = 1/3 pi r^2 h where r is the radius and h is the height

The diameter is 12 so the radius is 1/2 the diameter or 1/2(12) = 6

The height is 5 and we are using 3 for pi

V = 1/3 (3) *6^2 *5

V = 180 ft^3

4 0

3 years ago

1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6

meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

<u>2x-2y=-6 </u>

<u>7x =-21</u>

x= -3

Putting value of x in equation 1

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

Let

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ = A $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = X and $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$ = B

Then AX= B

or X= A⁻¹ B

where A⁻¹= adj A/ ║A║ where mod A≠ 0

adj A= $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$ $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}42\\0\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-3\\0\\\end{array}\right]$

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0

3 years ago

What is the solution to log (9x)-log 3 = 3?

xeze [42]

Answer:

The solution x = $\frac{e^{3} }{3}$

Step-by-step explanation:

<u>Step 1</u>:-

Given $log(9 x) -log 3 =3$

we have to use formula $log a-log b=log\frac{a}{b}$

$log(9 x)- log 3 = log(\frac{9 x}{3} )$ = $3$

Again by using formula $log a =b$

$a = e^{b}$

so $\frac{9 x}{3} =e^{3}$

<u>step 2:</u>-

$3 x = e^{3}$

$x = \frac{e^{3} }{3}$

The solution of given problem is $x=\frac{e^3}{3}$

5 0

3 years ago

Limit definition for slope of the graph, equation of tangent line point for<br> f(x)=2x^2 at x=(-1)

Tems11 [23]

The slope of the tangent line to $f$ at $x=-1$ is given by the derivative of $f$ at that point:

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}$

Factorize the numerator:

$2x^2-2=2(x^2-1)=2(x-1)(x+1)$

We have $x$ approaching -1; in particular, this means $x\neq-1$ , so that

$\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)$

Then

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4$

and the tangent line's equation is

$y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2$

6 0

3 years ago

Any suggestions or answers

Sati [7]

Answer:

$x=81\degree$

$y=99\degree$

$z=129\degree$

Step-by-step explanation:

The sum of the interior angles of a triangle is 180 degrees.

$\implies 51\degree+48\degree+x=180\degree$

$\implies 99\degree+x=180\degree$

$\implies x=180\degree-99\degree$

$\implies x=81\degree$

Use the exterior angles theorem to find y.

The exterior angle y is the sum of the two remote interior angles:

$y=51\degree+48\degree=99\degree$

The sum of angles on a straight line is 180 degrees.

$\implies z+51\degree=180\degree$

$\implies z=180\degree-51\degree$

$\implies z=129\degree$

7 0

3 years ago