Answer: y = (x +2)² + 5
<u>Step-by-step explanation:</u>
y = a(x - h)² + k <em>where "a" is the leading coefficient and (h, k) is the vertex</em>
Since we don't know "a", we need to plug in the point (x, y) and the vertex (h, k) to solve for "a": (x, y) = (0, 9) and (h, k) = (-2, 5)
y = a(x - h)² + k
9 = a(0 - (-2))² + 5
9 = a(0 + 2)² + 5
9 = a(2)² + 5
<u>-5 </u> <u> -5 </u>
4 = a(4)
<u>÷4 </u> <u> ÷4 </u>
1 = a
Next, plug in "a" and the vertex (h, k):
y = a(x - h)² + k
y = 1(x +2)² + 5
y = (x +2)² + 5
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First, think of your places. You have the ones places, tens places, hundreds places, and so on.
The first number starting from the right is the ones, and as you keep going left, the value of each given digit becomes higher.
Since 5 is in the ones place, its value would be just 5. If it were in the tens place, it would be 50. If it were in the hundreds place, it would be 500, and so on.
Think of it this way;
Ones is just one. If a number is in the 'ones' place, its value would be a single digit. If it were in the tens place, its value would be two digits.
That's how it would be for each place going left.
Every number you move to the left, its value gains a one.
So here's an example:
5555
The value of 5 in the ones place "5555" is simply 5.
In the tens place, you end up adding one zero, so the value of the second five to the left would be, "50"
So with that said, the value of the digit 5 in the number 75 is <em>5.
</em>Haha, hope this cleared up any confusion, and have a <em>wonderful </em>day! :)<em>
</em>
Answer:
60.3504
Step-by-step explanation:
Answer:11,058
Step-by-step explanation:
Just subtract
