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Angelina_Jolie [31]
4 years ago
9

The sum of liz's and melinda's ages is 28. if liz was 1/3 melinda's age 6 years ago, how old will liz be next year?

Mathematics
1 answer:
Mrrafil [7]4 years ago
3 0
The first thing we must do for this case is to define variables:
 We have then:
 x: liz's age
 y: melinda's age
 We now write the system of equations:
 x + y = 28

x-6 = (1/3) (y-6)
 By solving the system graphically we have that the age of each one is currently:
 x = 10

 y = 18
 Next year, the age of liz is:
 x + 1 = 10 + 1 = 11

 Answer:
 
Next year, Liz's age is 11 years.
 
Note: see attached image for the graphic solution.

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borishaifa [10]

Answer:

Both rates and ratios are a comparison of two numbers. A rate is simply a specific type of ratio. The difference is that a rate is a comparison of two numbers with different units, whereas a ratio compares two numbers with the same unit. For example, in a room full of students, there are 10 boys and 5 girls. This means the ratio of boys to girls is 10:5.

5 0
3 years ago
A coin is tossed 4 times. Let E1 be the event "the first toss shows heads" and E2 the event "the second toss shows heads" and so
Elden [556K]

Answer:

The events are independent.

The probability of showing heads on both toss is equal to 1/2

Step-by-step explanation:

The sample space for this experiment consists of 2⁴= 16 sample points, as each toss can result in two outcomes we assume that the events are equally likely.

Two events are independent in the sample space if the probability of one event occurs, is not affected by whether the other event has or has not occurred.

In general the k events are defined to be mutually independent if and only if the probability of the intersection of  any 2,3,--------, k  equals the product of their respective probabilities.

P (A∩B) = P(A). P(B)

P (A∩B)   = 1/2. 1/2= 1/4

                                                                  Head          Tail

 P(E1)= 1/2  ----------          Coin 1               H,H              T,H

                                                                1/4                  1/4

  P(E2)= 1/2  ---------------  Coin 2             H, H               H,T

                                                                      1/4           1/4

So the events are independent.

The probability of showing heads on both toss is equal to 1/2

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Or in other words ( 1/4* 1/4) = 2/4 = 1/2

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