Question

This table values that represent a quadratic function.

Answer 1

Answer:

A

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [ a, b ] = [ 3, 5 ] , thus

f(b) = f(5) = - 26 ← value of y for x = 5 from table

f(a) = f(3) = - 10 ← value of y for x = 3 from table

average rate of change = $\frac{-26-(-10)}{5-3}$ = $\frac{-16}{2}$ = - 8 → A