The density of gold is 19.3 g/cm3. What is the volume of a 575 gram bar of pure gold?
2 answers:
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Answer : The volume of oxygen at STP is 112.0665 L
Solution : Given,
The number of moles of = 5 moles
At STP, the temperature is 273 K and pressure is 1 atm.
Using ideal gas law equation :
where,
P = pressure of gas
V = volume of gas
n = the number of moles
T = temperature of gas
R = gas constant = 0.0821 L atm/mole K (Given)
By rearranging the above ideal gas law equation, we get
Now put all the given values in this expression, we get the value of volume.
Therefore, the volume of oxygen at STP is 112.0665 L