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Korvikt [17]
3 years ago
13

The given graduated cylinder is calibrated in

Chemistry
2 answers:
Marina CMI [18]3 years ago
8 0

Answer : The volume of liquid in graduated cylinder is 26.5 mL.

Explanation :

As we know that for the measurement of the volume of liquid in graduated cylinder are shown by placing the graduated cylinder on the flat surface and then view the height of the liquid in the graduated cylinder with the naked eyes directly level with the liquid.

The liquid will tend to curve downward that means this curve is known as the meniscus.

In the case of colored liquid, we are always read the upper meniscus of the liquid for the measurement.

In the case of colorless liquid, we are always read the lower meniscus of the liquid for the measurement.

In the given image, there are 10 division between the 20 and 30 and the solution is colorless. So, we will read the lower meniscus of the liquid for the measurement.

Hence, the volume of liquid in graduated cylinder is 26.5 mL.

matrenka [14]3 years ago
5 0

Answer: 26mL

Explanation:

You always need to see the meniscus of the liquid, (which is the curved figure in the liquid) in the cylinder, also, the question is telling you that write the correct number of significant figures, as the cylinder does not point at any decimal number, you cannot tell if it is on 26.1 or 26.9, you can be certain, only, that is 26 mL.

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PolarNik [594]

Answer:

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Explanation:

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6 0
2 years ago
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Studentka2010 [4]
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3 years ago
A sample of oxygen gas has a volume of 3.24 L at 29°C. What volume will it occupy at 104°C if the pressure and number of mol are
ohaa [14]

<u>Answer:</u> The final volume of the oxygen gas is 4.04 L

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=3.24L\\T_1=29^oC=(29+273)K=302K\\V_2=?\\T_2=104^oC=(104+273)K=377K

Putting values in above equation, we get:

\frac{3.24L}{302K}=\frac{V_2}{377K}\\\\V_2=4.04L

Hence, the final volume of the oxygen gas is 4.04 L

8 0
3 years ago
Describe a process that may have produced the moon
vaieri [72.5K]
The Giant-Impact theory. People basically believed that the moon was created from the collision between earth and another small planet:)
6 0
2 years ago
WILL GIVE BRAINLIEST! Explain how a pure metal is held together. Include a definition of a metallic bond in your explanation. Pl
vazorg [7]

Explanation:

A chemical bond which is formed in between positively charged atoms when there is sharing of free electrons in a lattice of cations is known as a metallic bond.

In a pure metal, atoms are surrounded by free moving valence electrons which move from one part of metal to another.

Thus, we can conclude that pure metals are held together by metallic bonds due to attraction between mobile valence electrons and positively charged metal ions.


7 0
3 years ago
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