Answer:
0.59 moles
Explanation:
Data Given
oxygen = 35 g
Moles of SeO₃ = ?
Reaction Given
2Se + 3O₂ ------> 2SeO₃
Solution:
Step 1.
First to find grams of SeO₃
So, we know from reaction that 2 mole of selenium combine with 3 mole of oxygen and produces 2 mole of SeO₃
2Se + 3O₂ ------> 2SeO₃
2mol 3 mol 2 mol
If we represent mole in grams
Then,
Molar mass of Se = 79 g/mol
Molar mass of O = 16 g/mol
Molar mass of SeO₃ = 79 + 3(16)
Molar mass of SeO₃ = 127 g/mol
2Se + 3O₂ ------> 2SeO₃
2mol (79 g/mol) 3 mol (32 g/mol) 2 mol (127 g/mol)
2Se + 3O₂ ------> 2SeO₃
158 g 96 g 206 g
It is obvious from the reaction that 96 g of oxygen gives 206 g of SeO₃.
Now how many grams of SeO₃ will produce if 35 grams of oxygen react with excess of Selenium
Apply unity formula
96 g of O₂ ≅ 206 g of SeO₃
35 g of O₂ ≅ x g of SeO₃
By doing cross multiplication
g of SeO₃ = 206 x 35 / 96
g of SeO₃ = 75 g
Step 2.
Convert grams of SeO₃ to mole
Formula used
no. of moles = mass in grams (SeO₃) / Molar mass of SeO₃
Put values in above formula
no. of moles = 75 g / 127 g/mol
no. of moles = 0.59 mol
So,
35 g of oxygen produces 0.59 moles of SeO₃
Answer:
6 number of complete triglycerides that could be formed .
Explanation:
In 25 microseconds ,single fatty acid attachment to glycerol takes place.
So, in 1 microseconds =
If the enzyme catalyzes dehydration synthesis reactions for 450 microseconds, then maximum numbers of attachments of fatty to glycerol will be:
And each triglycerides has three fatty acid chains.So, number of triglycerides formed will be :
6 number of complete triglycerides that could be formed if no fatty acids were bonded to glycerol at the beginning of the reactions
Answer:
For O: atomic number = 8 # neutrons = 8
For Al: atomic mass = 27, # electrons = 13
Answer:
0.11mole
Explanation:
Let us assume that the condition is at standard temperature and pressure(STP);
Given parameters:
Volume of water = 2.45L
Unknown:
Number of moles found in this volume of water = ?
Solution;
At STP;
Number of moles =
Input the parameters and solve;
Number of moles of water = = 0.11mole
The number of moles of water found is 0.11mole
Answer:
Option A is correct. The system is at equilibrium
Explanation:
Step 1: Data given
Kc at 1300 K = 5.00
Initial concentration of SO2 = 1.20 M
Initial concentration of O2 = 0.45 M
The concentration of SO3 = 1.80 M
When Q=K, the system is at equilibrium and there is no shift to either the left or the right.
When Q<K, there are more reactants than products. As a result, some of the reactants will become products, causing the reaction to shift to the right.
When Q>K, there are more products than reactants. To decrease the amount of products, the reaction will shift to the left and produce more reactants.
Step 2: The balanced equation
2 SO2(g) + O2(g) ⇌ 2 SO3(g)
Step 3: Calculate Q
Q = [SO3]² / [O2][SO2]²
Q = 1.80²/0.45*1.20²
Q = 5.00
Q = Kc
This means , the system is at equilibrium and there is no shift to either the left or the right.
Option A is correct.