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Aloiza [94]
3 years ago
12

Orange crayons are usually made in batches of 100. If it takes 22 pounds of wax to make 100 orange crayons,then how much wax wil

l you need to make one orange crayon?
Mathematics
1 answer:
bogdanovich [222]3 years ago
7 0

Amount of wax required for one orange crayon is 0.22 pounds.

Step-by-step explanation:

According to given statement;

22 pounds of wax = 100 orange crayons

For calculating wax for one crayon;

Wax required for one crayon = Total pounds of wax / Total no of crayons

Wax required for one crayon = \frac{22}{100}

Wax required for one crayon = 0.22

Amount of wax required for one orange crayon is 0.22 pounds.

Keywords: Crayon, Division.

Learn more about division at:

  • brainly.com/question/1949601
  • brainly.com/question/1952668

#LearnwithBrainly

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Step-by-step explanation:

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The difference is:

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Step-by-step explanation:

41 + 102 = 143

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Answer:

a) Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

b) t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

Step-by-step explanation:

Information given

\bar X=130 represent the sample mean for the amount spent each shopper

s=40 represent the sample standard deviation

n=80 sample size  

\mu_o =120 represent the value to verify

t would represent the statistic    

p_v represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:  

Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

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Step-by-step explanation:

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