1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
avanturin [10]
3 years ago
12

PLEASE HELP, I am desperate. This part of the presentation I am completely lost with. It is STEP 6, I got the rest finished.

Physics
1 answer:
yKpoI14uk [10]3 years ago
5 0

Answer:

Explanation:

Ok, pick some idea from here

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=10&ved=2ahUKEwjWoLaFypvnAhUowlkKHXZrCMkQFjAJegQIBBAB&url=https%3A%2F%2Fwww.wappingersschools.org%2Fcms%2Flib%2FNY01001463%2FCentricity%2FDomain%2F1552%2FGravity.ppt&usg=AOvVaw1N8kqPWy6ERpA3LNbbepit

You might be interested in
A 0.600 m long pendulum is used to determine the acceleration due to gravity on a distant plane. If 20 oscillations are complete
katrin2010 [14]

Answer:

7.50 m/s^2

Explanation:

The period of a pendulum is given by:

T=2\pi \sqrt{\frac{L}{g}} (1)

where

L = 0.600 m is the length of the pendulum

g = ? is the acceleration due to gravity


In this problem, we can find the period T. In fact, the frequency is equal to the number of oscillations per second, so:

f=\frac{N}{t}=\frac{20}{35.5 s}=0.563 Hz

And the period is the reciprocal of the frequency:

T=\frac{1}{f}=\frac{1}{0.563 Hz}=1.776 s

And by using this into eq.(1), we can find the value of g:

g=\frac{4 \pi^2 L}{T^2}=\frac{4 \pi^2 (0.600 m)}{(1.776 s)^2}=7.50 m/s^2

6 0
3 years ago
a man is 9 m behind a dorr of train when it starts moving with a=2ms^-1. how far the man have to run and after what time will he
Naya [18.7K]
Is their a multiple choice to choose from I'm not sure the answer I got is even right.
That would be very helpful.
8 0
3 years ago
What if m1 is initially moving at 3.4 m/s while m2 is initially at rest? (a) find the maximum spring compression in this case?
Lisa [10]
<span>Ans : Initial E = KE = ½mv² = ½ * 1.2kg * (2.2m/s)² = 2.9 J max spring compression where both velocities are the same: conserve momentum: 1.2kg * 2.2m/s = (1.2 + 3.2)kg * v → v = 0.6 m/s which means the combined KE = ½ * (1.2 + 3.2)kg * (0.6m/s)² = 0.79 J The remaining energy went into the spring: U = (2.9 - 0.79) J = 2.1 J = ½kx² = ½ * 554N/m * x² x = 0.0076 m ↠(a)</span>
7 0
3 years ago
Each ball has a negligible size and a mass of 11.5 kg and is attached to the end of a rod whose mass may be neglected. The rod i
Digiron [165]

Answer:

3.31m/s

Explanation:

Angular momentum for 3s is

L = L_i_n_i + L_3_s

L = 2(11.5kg) + \int\limits^ {3s}_ {0s} {(t^2 + 2)} \, dt

L = 23kg+(\frac{t^3}{3} +2t)^ {3s}_ {0s}\\\\L=38kgm/s

Moment if inertia is

I = 2ml^2

I = 2(11.5)(0.5)^2\\\\I=5.75kgm^2

Angular speed

ω = L/I

= 38 / 5.75\\\\=6.61

The speed of each ball is

V = ωL

= 6.61\times0.5\\\\= 3.31m/s

7 0
3 years ago
A person of mass 70 kg stands at the center of a rotating merry-go-round platform of radius 2.9 m and moment of inertia 900 kg⋅m
Cloud [144]

Explanation:

It is given that,

Mass of person, m = 70 kg

Radius of merry go round, r = 2.9 m

The moment of inertia, I_1=900\ kg.m^2

Initial angular velocity of the platform, \omega=0.95\ rad/s

Part A,

Let \omega_2 is the angular velocity when the person reaches the edge. We need to find it. It can be calculated using the conservation of angular momentum as :

I_1\omega_1=I_2\omega_2

Here, I_2=I_1+mr^2

I_1\omega_1=(I_1+mr^2)\omega_2

900\times 0.95=(900+70\times (2.9)^2)\omega_2

Solving the above equation, we get the value as :

\omega_2=0.574\ rad/s

Part B,

The initial rotational kinetic energy is given by :

k_i=\dfrac{1}{2}I_1\omega_1^2

k_i=\dfrac{1}{2}\times 900\times (0.95)^2

k_i=406.12\ rad/s

The final rotational kinetic energy is given by :

k_f=\dfrac{1}{2}(I_1+mr^2)\omega_1^2

k_f=\dfrac{1}{2}\times (900+70\times (2.9)^2)(0.574)^2

k_f=245.24\ rad/s

Hence, this is the required solution.

5 0
3 years ago
Other questions:
  • A car traveling at 50 m/s uniformly accelerates to 60 m/s over an 58 second interval. What is the displacement?
    10·2 answers
  • A student is trying to calculate the density of a ball. She already knows the mass, but she needs to determine the volume as wel
    6·1 answer
  • Below are two of the seven original Axioms of URT.
    8·1 answer
  • For each of the following statements determine whether it is correct or incorrect.
    10·1 answer
  • A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket
    8·1 answer
  • As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.09 mm apart and position
    11·1 answer
  • ANSWER THIS QUESTION PLS WILL GIVE BRAINLEST
    9·2 answers
  • What is air resistance means explain it with free falling body​
    10·1 answer
  • If I start with an 30 gram sample of Plutonium-244, how many grams would be left of Plutonium-244 after 1 half life
    6·1 answer
  • Please look at the picture and answer the questions
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!