Answer:
send the wagon down a higher hill
W=20 e(-kt)
A. Rearranging gives k= -(ln(w/20)/t
Substituting w= 10 and solving gives k=0.014
B. Using W=20e(-kt). After 0 hours, W=20. After 24 hours, W=14.29g. After 1 week (24x7=168h) W=1.9g
C. Rearranging gives t=-(ln(10/20)/k. Substituting w=1 and solving gives t=214 hours.
D. Differentiating gives dW/ dt = -20ke(-kt). Solving for t=100 gives dW/dt = 0.07g/h. Solving for t=1000 gives 0.0000002g/h
E. dW/dt = -20ke(-kt). But W=20e(-kt) so dW/dt = -kW
Answer:
The work done is 5136.88 J.
Explanation:
Given that,
n = 1.90 mol
Temperature = 296 K
If the initial volume is V then the final volume will be V/3.
We need to calculate the work done
Using formula of work done
Put the value into the formula
The Work done on the system.
Hence, The work done is 5136.88 J.