Answer:
4m/s2
Explanation:
The following data were obtained from the question:
U (initial velocity) = 10m/s
V (final velocity) = 30m/s
t (time) = 5secs
a (acceleration) =?
Acceleration is the rate of change of velocity with time. It is represented mathematically as:
a = (V - U)/t
Now, with this equation i.e
a = (V - U)/t, we can calculate the acceleration of the race car as follow:
a = (V - U)/t
a = (30 - 10)/5
a = 20/5
a = 4m/s2
Therefore, the acceleration of the race car is 4m/s2
Answer:option C
Explanation:
Angular momentum equal to radius times linear momentum
So ang momentum equal to
1 meter x (MV)
1 m x (1.25 kg x 180 m/s)
225 kg m square/second
Hence option C
<h2>Yes, it has cell structure with a membrane and nucleus.</h2>
The rider's horizontal motion, and how much ground he covers before he hits it, have nothing to do with how long he takes to hit the ground. The problem is simply: "How long does it take an object to fall 1.12 m from rest ?"
This seems like a good time to use this formula:
Distance fallen from rest = (1/2) (acceleration) (time)²
The problem doesn't tell us what planet the skateboarder is exercising on. I'm going to assume it's on Earth, where the acceleration of gravity is 9.8 m/s². And now, here's the solution to the problem I just invented:
1.12 m = (1/2) (9.8 m/s²) (time)²
Time² = (1.12 m) / (9.8 m/s²)
Time² = 0.1143 sec²
Time = √(0.1143 sec² )
<em>Time = 0.34 second</em>
Forgot to measure the volume in the beginning so the student could tell the difference
