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aliya0001 [1]
3 years ago
11

Find the Mean, Median and Mode of the data set:

Mathematics
1 answer:
Paul [167]3 years ago
8 0

Answer:

Mode = 37

Mean = 26.1

median = 30

Step-by-step explanation:

have a good day!!!!

To find the mean add all then divide by how many are for example:

(8+ 32+ 41+ 6+ 36+ 10+ 37+ 31 +29+ 37+ 32+ 11+ 30+ 15+ 23+ 37+ 34+17+29) /19= 26.1

To find the mode find the number that most appear in the data set

To  find the median organiz the data set from in a crecent order then find the number in the middle.

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Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks. Quincy and his mo
Vikentia [17]

Step-by-step explanation:

rc = planted rows of carrots

rt = planted rows of tomatoes

h = number of hours

rc = 4h + 1 (starting with 1 already finished row there will be 4 additional rows every hour)

rt = 3h + 8 (staying with 8 already finished rows there will be 3 additional rows every hour).

when will they have planned the same number of rows ?

when rc = rt, of course.

so,

4h + 1 = 3h + 8

h = 7

4×7 + 1 = 28 + 1 = 29 rows

after 7 hours Quincy and his mom will each have planted 29 rows of vegetables.

8 0
2 years ago
The cube has a volume of 27 in3. Find the volume of a scaled image with a scale factor of 2. in3 Cube with a side length of thre
WINSTONCH [101]
The new size of cube's side is 6. V new cube = 6*6*6 = 216 

7 0
3 years ago
Y is inversely proportional to V1+x.<br> When x = 8, y = 2.<br> Find y when x = 15.
murzikaleks [220]

Answer:

y = 1.5

Step-by-step explanation:

Given x is inversely proportional to \sqrt{1+x} , then the equation relating them is

y = \frac{k}{\sqrt{1+x} } ← k is the constant of proportion

To find k use the condition when x = 8, y = 2

2 = \frac{k}{\sqrt{1+8} } = \frac{k}{\sqrt{9} } = \frac{k}{3} ( multiply both sides by 3 )

6 = k

y = \frac{6}{\sqrt{1+x} } ← equation of proportion

When x = 15 , then

y = \frac{6}{\sqrt{1+15} } = \frac{6}{\sqrt{16} } = \frac{6}{4} = \frac{3}{2} = 1.5

6 0
2 years ago
Solve (4 - x ≤ -1) ∩ (2 + 3x ≥ 17).
belka [17]
4-x \leq -1\ \ \ | subtract\ 4\ \ \ \ \ and\ \ \ \ 2+3x \geq 17\ \ \ | subtract\ 2\\\\&#10;-x \leq -5\ |*(-1)\ \ \ \ and\ \ \ \ 3x \geq 15\ \ | divide\ by\ 3\\\\&#10;x \geq 5\ \ \ \ \ and\ \ \ \ x \geq 5\\\\&#10;Solution\ is\ x\in[5,+\infty)
3 0
3 years ago
Read 2 more answers
Find the area of the figure:  Select one: a. 59.5 yd^2 b. 81 yd^2 c. 58.5 yd^2 d. 55.3 yd^2
lions [1.4K]
Answer would be 58.5 yd^2 .

You should take the base of the triangle multiplied by the height.

Formula: 1/2×base×height

In this case, you know that base is 13yd and height is 9 yd.

So, apply the formula.

Area = 1/2(13yd)(9yd) = 58.5 yd^2

*Do not include the " invisible length as it is not part of the actual triangle.

*Do not include 32yd as it is a hypotenuse and not a base. Hypotenuse is a side that is opposite a right angle triangle.
8 0
3 years ago
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