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aliya0001 [1]
3 years ago
11

Find the Mean, Median and Mode of the data set:

Mathematics
1 answer:
Paul [167]3 years ago
8 0

Answer:

Mode = 37

Mean = 26.1

median = 30

Step-by-step explanation:

have a good day!!!!

To find the mean add all then divide by how many are for example:

(8+ 32+ 41+ 6+ 36+ 10+ 37+ 31 +29+ 37+ 32+ 11+ 30+ 15+ 23+ 37+ 34+17+29) /19= 26.1

To find the mode find the number that most appear in the data set

To  find the median organiz the data set from in a crecent order then find the number in the middle.

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we believe that 42% of freshmen do not visit their counselors regularly. For this year, you would like to obtain a new sample to
Maksim231197 [3]

Answer:

A sample of 1077 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

42% of freshmen do not visit their counselors regularly.

This means that \pi = 0.42

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

How large of a sample size is required?

A sample size of n is required, and n is found when M = 0.035. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.035 = 2.327\sqrt{\frac{0.42*0.58}{n}}

0.035\sqrt{n} = 2.327\sqrt{0.42*0.58}

\sqrt{n} = \frac{2.327\sqrt{0.42*0.58}}{0.035}

(\sqrt{n})^2 = (\frac{2.327\sqrt{0.42*0.58}}{0.035})^2

n = 1076.8

Rounding up:

A sample of 1077 is required.

3 0
3 years ago
Drag numbers to the table so it shows a proportional relationship between x and y.
Yakvenalex [24]

Answer:

the second box for y is 9

the third box for x is 2.5

im not sure about the third box for y

8 0
2 years ago
(Segment Proofs)
Anni [7]

Answer:

It's proved below

Step-by-step explanation:

We are given;

- K is the midpoint of JL

- M is the midpoint of LN

By definition of mid points, we can say that;

JK = KL and LM = MN

Now, we are given that JK = MN.

Thus, by substitution, we can deduce that; KL = LM

Thus is because JK can be replaced with KL and MN can be replaced with LM.

Thus, it is proved that KL = LM

4 0
3 years ago
Square ABCD is shown with four congruent images such that ABCD FGHI JKLM NOPQ RSTU.
N76 [4]

FGHI

Step-by-step explanation:

The square FGHI needs to be created into a reflection for true congruence of the figure thus transformed across the axis.

FGHI's co-ordinates' signs are to be reversed for reflection thus coordinates:

2,-5

4,-5

2,-7

4,-7

are made into

-2,5

-4,5

-2,7

-4,7

5 0
3 years ago
Read 2 more answers
13) A rectangular garden has an area of 45 square meters. The garden will be 4 meters longer than its width Write and sowe an eq
11Alexandr11 [23.1K]

Answer:

9m ×5m

Step-by-step explanation:

Area of a rectangle= length ×width

Let the width be W meters and the length be L meters.

2 equations can be written from the given information:

45= WL -----(1)

L= W +4 -----(2)

Substitute (2) into (1):

45= W(W +4)

<em>Expand:</em>

45= W² +4W

<em>-45 on both sides:</em>

W² +4W -45= 0

<em>Factorise:</em>

(W +9)(W -5)= 0

W+9=0 or W-5=0

W= -9 or W= 5

(reject)

Substitute W= 5 into (2):

L= 5 +4

L= 9

∴ The dimensions of the garden is 9m ×5m.

6 0
3 years ago
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