Answer:
a) t = 56.34 minutes
b) v = 5.32mph
c) t = 47.22 minutes
d) v = 6.35 mph
Explanation:
Given;
The speed of Ilya and Anya are
Run = 8.90mph
Walk = 3.80mph
distance = 5.00 miles
a) anya walk half the distance and run half the distance.
Speed = distance/time
time = distance/speed
t1 = 5×0.5/3.80 = 0.658hr
t2 = 5×0.5/8.90 = 0.281hr
t = t1 + t2 = 0.658+0.281 = 0.939hr × 60minutes/hr
t = 56.34 minutes
b) average speed = total distance/total time taken
v = 5.00miles/0.939hr = 5.32mph
c) Ilya walk half the time and run half the time.
t1 = t2 = t/2
Distance = speed × time
Substituting the values.
5 = 3.80(t/2) + 8.90(t/2)
5 = 12.70(t/2)
t = 10/12.70
t = 0.787 hr × 60 minutes/hr
t = 47.22 minutes
d) average speed = 5miles/0.787hr
v = 6.35 mph
1. Find the spring constant k:
F = mg = kx
68 * g = k * 0.0055m
k = 121287.273
2.Find the frequency f:
ω = 2πf = √k/m
f = √(k / m)/ 2π = 1.7
Answer:
the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.
The tangential speed of an orbiting object is 
Explanation:
The tangential speed of an orbiting object is defined as the ratio between the distance covered in one revolution and the period of revolution:

where
d is the distance covered during one period
T is the orbital period
However, the distance covered during one period is the circumference of the circle:

where
r is the radius of the circle
Substituting the 2nd equation into the 1st equation, we find:

So, this is the final expression for the tangential speed of an orbiting object.
Learn more about circular motion:
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