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Tamiku [17]
3 years ago
7

If an object falls with constant acceleration, the velocity of the object must continually change by varying amounts, depending

on its speed.
be constant also.
continually change by the same amount each second.
continually decrease.
none of the above
Physics
1 answer:
Ierofanga [76]3 years ago
3 0

Answer:

continually change by the same amount each second

Explanation:

We all are aware  with the fact that a car speeds is increased when we put our feet  on the accelerator. The rate at which the particle's velocity change with time is called its acceleration. If the particle's velocity changes with constant rate, then its rate is called the constant acceleration.

Since the basic units are meter and seconds. And the SI unit of velocity is m/s and acceleration's SI unit is m/s^{2}

For example if the velocity is change from 2 to 4 m/s in 1 sec its acceleration is 2m/s^{2} and again its velocity is change with 4 m/s to 6 m/s will again give constant acceleration in 1 s is 2m/s^{2}.

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In a charming 19th-century hotel, an old-style elevator is connected to a counterweight by a cable that passes over a rotating d
melisa1 [442]

Answer:

2.38732 rpm

1.22625 rad/s²

163.292°

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

a = Acceleration = \frac{1}{8}g

d = Diameter of wheel = 2 m

r = Radius of wheel = \frac{d}{2}=\frac{2}{2}=1\ m

v = Speed of elevator = 25 cm/s

Angular speed is given by

\omega=\frac{v}{r}\\\Rightarrow \omega=\frac{0.25}{1}\\\Rightarrow \omega=0.25\ rad/s=0.25\times \frac{60}{2\pi}\\\Rightarrow \omega=2.38732\ rpm

The angular speed of the wheel is 2.38732 rpm

Angular acceleration is given by

\alpha=\frac{a}{r}\\\Rightarrow \alpha=\frac{\frac{1}{8}g}{r}\\\Rightarrow \alpha=\frac{\frac{1}{8}\times 9.81}{1}\\\Rightarrow \alpha=1.22625\ rad/s^2

The angular acceleration of the wheel is 1.22625 rad/s²

Angular displacement is given by

\theta=\frac{s}{r}\\\Rightarrow \theta=\frac{2.85}{1}\\\Rightarrow \theta=2.85\ rad=2.85\times \frac{360}{2\pi}\\ =163.292\ ^{\circ}

The angle the disk turned when it has raised the elevator is 163.292°

4 0
3 years ago
A force of 120 N is exerted on a 40 kg container which sits on a floor. If the frictional force between floor and container is 8
harkovskaia [24]

Answer:

Magnitude is 144N .

Explanation:

a²+b²=c²

120N²+80N²=c²

14400+6400=c²

\sqrt{20800}   =  \sqrt{c} ^{2}

144N=c

7 0
3 years ago
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