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Tamiku [17]
3 years ago
7

If an object falls with constant acceleration, the velocity of the object must continually change by varying amounts, depending

on its speed.
be constant also.
continually change by the same amount each second.
continually decrease.
none of the above
Physics
1 answer:
Ierofanga [76]3 years ago
3 0

Answer:

continually change by the same amount each second

Explanation:

We all are aware  with the fact that a car speeds is increased when we put our feet  on the accelerator. The rate at which the particle's velocity change with time is called its acceleration. If the particle's velocity changes with constant rate, then its rate is called the constant acceleration.

Since the basic units are meter and seconds. And the SI unit of velocity is m/s and acceleration's SI unit is m/s^{2}

For example if the velocity is change from 2 to 4 m/s in 1 sec its acceleration is 2m/s^{2} and again its velocity is change with 4 m/s to 6 m/s will again give constant acceleration in 1 s is 2m/s^{2}.

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Ilya and Anya each can run at a speed of 8.90mph and walk at a speed of 3.80mph . They set off together on a route of length 5.0
jekas [21]

Answer:

a) t = 56.34 minutes

b) v = 5.32mph

c) t = 47.22 minutes

d) v = 6.35 mph

Explanation:

Given;

The speed of Ilya and Anya are

Run = 8.90mph

Walk = 3.80mph

distance = 5.00 miles

a) anya walk half the distance and run half the distance.

Speed = distance/time

time = distance/speed

t1 = 5×0.5/3.80 = 0.658hr

t2 = 5×0.5/8.90 = 0.281hr

t = t1 + t2 = 0.658+0.281 = 0.939hr × 60minutes/hr

t = 56.34 minutes

b) average speed = total distance/total time taken

v = 5.00miles/0.939hr = 5.32mph

c) Ilya walk half the time and run half the time.

t1 = t2 = t/2

Distance = speed × time

Substituting the values.

5 = 3.80(t/2) + 8.90(t/2)

5 = 12.70(t/2)

t = 10/12.70

t = 0.787 hr × 60 minutes/hr

t = 47.22 minutes

d) average speed = 5miles/0.787hr

v = 6.35 mph

5 0
3 years ago
Where is most of Earth’s freshwater found?
STALIN [3.7K]
In lakes and streams
5 0
3 years ago
The springs of a 1000 kg car compress 5.5 mm when its 68 kg driver gets into the driver's seat. If the car goes over a bump, wha
zimovet [89]
1. Find the spring constant k:

F = mg = kx
68 * g = k * 0.0055m

k = 121287.273

2.Find the frequency f:
ω = 2πf = √k/m 

f = √(k / m)/ 2π =  1.7
4 0
3 years ago
What is kinematics?? koi Hindustani online h kya?​
AlexFokin [52]

Answer:

the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.

3 0
3 years ago
Read 2 more answers
Which formula can be used to find the tangential speed of an orbiting object?
Galina-37 [17]

The tangential speed of an orbiting object is v=\frac{2\pi r}{T}

Explanation:

The tangential speed of an orbiting object is defined as the ratio between the distance covered in one revolution and the period of revolution:

v=\frac{d}{T}

where

d is the distance covered during one period

T is the orbital period

However, the distance covered during one period is the circumference of the circle:

d=2\pi r

where

r is the radius of the circle

Substituting the 2nd equation into the 1st equation, we find:

v=\frac{2\pi r}{T}

So, this is the final expression for the tangential speed of an orbiting object.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

4 0
4 years ago
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