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Alex73 [517]
3 years ago
14

Where is most of Earth’s freshwater found?

Physics
1 answer:
STALIN [3.7K]3 years ago
5 0
In lakes and streams
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You observe lighting striking and then hear to sound 8 seconds later. The speed of sound in air is 340 m/s. How
Leto [7]

Answer:

2.72 Kilometers

Explanation:

8 × 340 m/s = 2720 m = 2.72 Kilometers

7 0
2 years ago
A traveling wave on a string can be described by the equation : y = (5.26 ~\text{m}) \cdot \sin \big( (1.65 ~\frac{\text{rad}}{\
zloy xaker [14]

Answer:

  t = 1.77 s

Explanation:

The equation of a traveling wave is

       y = A sin [2π (x /λ -t /T)]

where A is the oscillation amplitude, λ the wavelength and T the period

the speed of the wave is constant and is given by

      v = λ f

Where the frequency and period are related

     f = 1 / T

we substitute

      v = λ / T

let's develop the initial equation

    y = A sin [(2π / λ) x - (2π / T) t +Ф]

where Ф is a phase constant given by the initial conditions

the equation given in the problem is

    y = 5.26 sin (1.65 x - 4.64 t + 1.33)

if we compare the terms of the two equations

 

         2π /λ = 1.65

          λ = 2π / 1.65

          λ = 3.81 m

         2π / T = 4.64

          T = 2π / 4.64

          T = 1.35 s

we seek the speed of the wave

           v = 3.81 / 1.35

           v = 2.82 m / s

           

Since this speed is constant, we use the uniformly moving ratios

          v = d / t

           t = d / v

           t = 5 / 2.82

           t = 1.77 s

3 0
3 years ago
A person standing a certain distance from four identical loudspeakers is hearing a sound level intensity of 125 dB. What sound l
DENIUS [597]

Answer:

\mathbf{\beta = 123.75 \ dB}

Explanation:

From the question, using the expression:

125 \ dB = 10 \ log (\dfrac{I}{I_o})

where;

I_o = 10^{-12} \ W/m^2

I = 10^{12.5} \times 10^{-12} \ W/m^2

I = 3.162 \ W/m^2

This is a combined intensity of 4 speakers.

Thus, the intensity of 3 speakers = \dfrac{3.162\times 3}{4}

= 2.372 W/m²

Thus;

\beta = 10 \  log ( \dfrac{2.372}{10^{-12}} ) \ W/m^2

\mathbf{\beta = 123.75 \ dB}

7 0
3 years ago
NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts the supp
IRINA_888 [86]

Complete question :

NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts the supply storage area of the lunar outpost where gravity is 1.63m/s/s can only support 1 x 10 over 5 N. What is the maximum WEIGHT of supplies, as measured on EARTH, NASA should plan on sending to the lunar outpost?

Answer:

601000 N

Explanation:

Given that :

Acceleration due to gravity at lunar outpost = 1.6m/s²

Supported Weight of supplies = 1 * 10^5 N

Acceleration due to gravity on the earth surface = 9.8m/s²

Maximum weight of supplies as measured on EARTH :

Ratio of earth gravity to lunar post gravity:

(Earth gravity / Lunar post gravity) ;

(9.8 / 1.63) = 6.01

Hence, maximum weight of supplies as measured on EARTH should be :

6.01 * (1 × 10^5)

6.01 × 10^5

= 601000 N

3 0
3 years ago
A roller coaster car speed is 4 m/s, but 3 seconds later its speed is 22 m/s. What is its average acceleration?
Juli2301 [7.4K]
The velocity increased from 4 m/s to 22 m/s in 3 seconds. 18 m/s in 3 seconds so the average acceleration is change in velocity divided by time. 18 m/s divided by 3 seconds = 6 m/s^2
6 0
3 years ago
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