Answer:
the thermal energy generated in the loop = 
Explanation:
Given that;
The length of the copper wire L = 0.614 m
Radius of the loop r = 
r = 
r = 0.0977 m
However , the area of the loop is :
Change in the magnetic field is 
Then the induced emf e = 
e = 
e = 2.74 × 10⁻³ V
resistivity of the copper wire 
Ω m
diameter of the wire = 1.08 mm
radius of the wire = 0.54 mm = 0.54 × 10⁻³ m
Thus, the resistance of the wire R = 
R = 
R = 1.13× 10⁻² Ω
Finally, the thermal energy generated in the loop (i.e the power) = 
= 
=
Group 0 - they are called the NOBLE GASES
(as they're very unreactive) because...
ALL of their atoms are full.
Example : Helium contains 2 electrons so it's outer shell is full
Answer:
in 90 seconds It'll travel 450m At constant speed of 5m/s
Answer:
2991.42 N
Explanation:
For this problem, we'll use the equations: momentum= mass x velocity and impulse = change in momentum, and impulse=force x time.
initial momentum; p1 = 0.17 x 41 = 6.97 kg.m/s
final momentum; p2 = 0, because final velocity is 0 m/s
Thus,
impulse = p1 - p2= 6.97 - 0 = 6.97 kg.m/s
Finally, impulse= Force x time,
Thus, Force = Impulse/time
Force= 6.97/ (2.33 x 10^(-3)) = 2991.42 N
Proceed to go when the light turns green with caution watching out for other drivers to prevent and accident
