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3 years ago

How dose the hypothesis and observations connect

Physics

1 answer:

gavmur [86]3 years ago

7 0

Answer:

In the observational method, the hypothesis is constructed to explain the observations. A simple one may be a generalization of the observations. A more complex hypothesis may postulate a relationship between the events, and may even be used to predict other observations.

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The highest frequency radio waves are which type ?

Zolol [24]

Answer: Gamma rays

Explanation: Gamma rays have the highest energies, the shortest wavelengths, and the highest frequencies.

7 0

4 years ago

At the nose of a missile in flight, the pressure and temperature are 5.6 atm and 850°R, respectively. Calculate the density and

Contact [7]

To solve this problem we will apply the definition of the ideal gas equation, where we will clear the density variable. In turn, the specific volume is the inverse of the density, so once the first term has been completed, we will simply proceed to divide it by 1. According to the definition of 1 atmosphere, this is equivalent in the English system to

$1atm = 2116lb/ft^2$

The ideal gas equation said us that,

PV = nRT

Here,

P = pressure

V = Volume

R = Gas ideal constant

T = Temperature

n = Amount of substance (at this case the mass)

Then

$\frac{n}{V} = \frac{P}{RT}$

The amount of substance per volume is the density, then

$\rho = \frac{P}{RT}$

Replacing with our values,

$\rho = \frac{5.6*2116}{1716*850}$

$\rho = 0.00812slug/ft^3$

Finally the specific volume would be

$v = \frac{1}{\rho}$

$v = 123ft^3/slug$

6 0

3 years ago

A bucket weighing 5 lbs is lifted at a constant rate from the bottom of a 100 ft well by a rope which weighs 5 lbs. The bucket h

8_murik_8 [283]

Answer:

$W_{bucket} = 24934.85\,lbf\cdot ft$

Explanation:

The system is modelled after the Principle of Energy Conservation and the Work-Energy Theorem:

$W_{bucket} = U_{g,B, bucket} - U_{g,A,bucket} +U_{g, B, water}-U_{g,A,water} +U_{g, B, rope} -U_{g,A,rope}$

$W_{bucket} = (5\,lb) (32.174\,\frac{ft}{s^{2}})\cdot (100\,ft-0\,ft) + (25\,lb)\cdot (32.174\,\frac{ft}{s^{2}})\cdot (100\,ft) - (30\,lb)\cdot (32.174\,\frac{ft}{s^{2}})\cdot (0\,ft)+(5\,lb) (32.174\,\frac{ft}{s^{2}})\cdot (100\,ft-50\,ft)$