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AveGali [126]
3 years ago
15

Factorise:2x^4+x^3-14x^2-19x-6

Mathematics
1 answer:
tester [92]3 years ago
6 0

Answer:

(x+1)(2x+1)(x+2)(x−3)

Step-by-step explanation:

Factor 2x^4+x^3−14x^2−19x^−6

2x^4+x^3−14x^2−19x^−6

=(x+1)(2x+1)(x+2)(x−3)

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In Cos A = 0.4 Find The Value Of Cos 3 A.<br><br><br><br>Thenku ☃️<img src="https://tex.z-dn.net/?f=%20%5C%3A%20%5C%3A%20" id="T
s2008m [1.1K]
Answer:
- 0.944

Step-by-step explanation:
We know that,
cos 3A = 4 cos³A - 3 cos A (formula)

So,
If cos A = 0.4,

cos 3A = 4 cos³A - 3 cos A
cos 3A = 4 × (0.4)³ - 3 × (0.4)
cos 3A = 4 × 0.064 - 1.2
cos 3A = - 0.944


Hope it helps ⚜




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