Question

A garden hose with a small puncture is stretched horizontally along the ground. The hose is attached to an open water faucet at one end and a closed nozzle at the other end. As you might suspect, water pressure builds up and water squirts vertically out of the puncture to a height of 0.93 m. Determine the pressure inside the hose. (Enter your answer to the nearest 1000 P

Answer 1

Answer:110.439 KPa

Explanation:

Given

Height to which water is raised $h=0.93 m$

assuming $P_{atm}=101.325 KPa$

Applying Bernoulli's equation between Pipe Puncture and highest Point we get

$P_1+0.5\rho v_1^2+\rho gh_1=P_2+0.5\rho v_2^2+\rho gh_2$

$v_1=0,h_1=0,v_2=0$

we get

$P_1-P_{atm}=\rho gh$

$\Delta P=10^3\times 9.8\times 0.93$

$P_1=P_{atm}+9.114$

$P_1=101.325+9.114=110.439 KPa$