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4 years ago

What will happen to a material made of rubber if struck by lightning

Physics

1 answer:

Sunny_sXe [5.5K]4 years ago

7 0

Rubber acts as an insulator, and rubber tires or rubber shoes can protect you from being struck by lightning.

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Calculate the pressure exerted on a surface by a brick of weight 10 N. The area in contact with the surface is 20 cm2

anzhelika [568]

Answer:

Explanation:

Force of brick = 10 N

Area of surface = 20 cm^2

Pressure = force / area

∴ Pressure = 10 / 20

= 1 / 2 or 0.5 Pa

Hope this hepls

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7 0

3 years ago

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What is the difference between vehicle borne and vector borne transmission?

Ugo [173]

Vehicle borne transmission is an indirect transmission of an infectious organism when the host of the organism is in contact with another potential host. Vector borne, on the other hand, happens when there is a transmitter involved causing the spread of the disease. This transmitter is called the vector.

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4 years ago

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A 5.7 kg particle starts from rest at x = 0 and moves under the influence of a single force Fx = 4.5 + 13.7 x − 1.5 x 2 , where

const2013 [10]

Answer:

The work done by the force on the particle is 29.85 J.

Explanation:

The work is given by:

$W = ^{x_{2}}_{x_{1}}\int F_{x} dx$

Where:

x₁: is the lower limit = 0 m

x₂: is the upper limit = 1.9 m

Fₓ: is the force in the horizontal direction = (4.5 + 13.7x - 1.5x²)N

$W = ^{1.9}_{0}\int (4.5 + 13.7x - 1.5x^{2}) dx$

$W = 4.5x|^{1.9}_{0} + \frac{13.7}{2}x^{2}|^{1.9}_{0} - \frac{1.5}{3}x^{3}|^{1.9}_{0}$

$W = 4.5N(1.9 m) + \frac{13.7N}{2}(1.9 m)^{2} - \frac{1.5N}{3}(1.9 m)^{3}$

$W = 29.85 J$

Therefore, the work done by the force on the particle is 29.85 J.

I hope it helps you!

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3 years ago

A 0.03 kg golf ball is hit off the tee at a speed of 34 m/s. The golf club was in contact with the ball for 0.003 s. What is the

Liula [17]

Answer:

The average force on ball by the golf club is 340 N.

Explanation:

Given that,

Mass of the golf ball, m = 0.03 kg

Initial speed of the ball, u = 0

Final speed of the ball, v = 34 m/s

Time of contact, $\Delta t=0.003\ s$

We need to find the average force on ball by the golf club. We know that the rate of change of momentum is equal to the net external force applied such that :

$F=\dfrac{\Delta p}{\Delta t}\\\\F=\dfrac{mv-mu}{\Delta t}\\\\F=\dfrac{mv}{\Delta t}\\\\F=\dfrac{0.03\ kg\times 34\ m/s}{0.003\ s}\\\\F=340\ N$

So, the average force on ball by the golf club is 340 N.

4 0

4 years ago

Which of the following is a feature of the sun's radiation?

Firdavs [7]

The sun's radiation is made up of rays of many different wavelengths.

8 0

3 years ago

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