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lara [203]
3 years ago
8

If a runner has a speed of 8.66m/s and runs for 46.2s what distance is covered? tv = d

Physics
1 answer:
kati45 [8]3 years ago
6 0

Answer:

\text{Using the formula: }v=\frac{d}{t}\\\therefore vt=d\\\text{Plug and chug:}46.2(8.66)=400.092\text{ metres}

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A stone is dropped from a high cliff vertically. After 6
bonufazy [111]

Answer:

Ay=v₂t + ½ gt² is the best choice to solve this problem.

The height of the cliff is = 176.4 meters.

Explanation:

Given,

initial velocity = 0m/s as it is dropped vertically

acceleration = g = 9.8 m/s²

time = 6s

Height =?

Using the equation Ay=v₂t + ½ gt², we can calculate Ay, which is the height.

So,

Ay=v₂t + ½ gt²

by substituting v, t, and g, we get:

Ay= 0 × 6 + ½ × 9.8 × 6²

Ay = 0 + 4.9 × 36

Ay = 176.4 m

4 0
1 year ago
Two clowns are launched from the same spring-loaded circus cannon with the spring compressed the same distance each time. Clown
sweet-ann [11.9K]

Answer:

the kinetic energy of clown A is 0.444 times the kinetic energy of clown B.

Explanation:

Let the spring constant of the spring is k.

For clown A:

m = 40 kg

let the extension in the spring is y.

So, the spring force, F = k y

m g = k y

40 x g = k x y

y = 40 x g / k      ..... (1)

For clown B:

m' = 60 kg

Let the extension in the spring is y'.

So, the spring force, F' = k y'

m' g = k y'

y' = 60 x g / k      .....(2)  

Kinetic energy for A, K = 1/2 ky^2

Kinetic energy for B, K' = 1/2 ky'^2

So, K/K' = y^2/y'^2 K / K' = (40 x 40) / (60 x 60)     (from equation (1) and (2))

K / K' = 0.444

K = 0.444 K'

So the kinetic energy of clown A is 0.444 times the kinetic energy of clown B.

5 0
3 years ago
A diffraction grating, ruled with 300 lines per mm, is illuminated with a white light source at normal incidence.
Vera_Pavlovna [14]

the expression for diffraction grating allows to find the results for the questions for the angular separation are:

i) The third order is Δθ = 0.203 rad.

ii) The first order with water is Δθ = 0.046 rad.

The diffraction grating is a system formed by a large number of equally spaced lines whose diffraction is given by the expression.

          d sin θ = m λ

Where d is the distance between two lines, θ is the angle of diffraction, the order of diffraction and λ is the wavelength.

i) Let's start by looking for the separation between two lines

Let's use a rule of direct proportions. If there are 300 lines in 1 mm, what distance is there between two lines.

         d = 1 lines (1 mm / 300 lines) = 3,333 10⁻³ mm

         d = 3.333 10⁻⁶ m

Let's find the angle of diffraction for the third order (m = 3) for each wavelength.

λ₁ = 400 nm = 400 10⁻⁹ m

         sin θ₁ = \frac{m \ \lambda }{d}m λ/ d

         sin θ₁ = \frac{3 \ 400 \ 10^{-9} }{3.333 \ 10^{-6} }  

         θ₁ = sin⁻¹ 0.3600

         θ₁ = 0.368 rad

λ₂ = 600 nm = 600 10⁻⁹ m

         sin θ₂ = \frac{3 \ 600 \ 10^{-9} }{3.333 \ 10^{-6} }  

         θ₂ = sin⁻¹ 0.5401

         θ₂ = 0.571 rad

The angular separation is

         Δθ = θ₂ - θ₁

         Δθ = 0.571 - 0.368

         Δθ = 0.203 rad

ii) In this case, the separation between the network and the observation screen is filled with water.

When the rays leave the network they undergo a refraction process, for which they must comply with the relationship.

           n_i \ sin \theta_1 = n_r \ sin \theta_r

The incident side is in the air, therefore its refractive index is n_i = 1 and when it passes into the water with refractive index n_r = 1.33.

Let's start looking for the incident angles for the first order of diffraction.

      m = 1

λ₁ = 400 nm

         θ₁ = sin⁻¹  \frac{1 \ 400 \ 10^{-9}}{3.33 \ 10^{-6}}

         θ₁ = 0.120 rad

λ₂ = 600 nm

        θ₂ = sin⁻¹¹ \frac{1 \ 600 \ 10^{-9} }{3.33 \ 10^{-6}}

        θ₂ = 0.181 rad

we use the equation of refraction.

         \theta_r  = sin⁻¹ (\frac{n_i}{n_r} \ sin \ \theta_i )

λ₁ = 400 nm  

       θ₁ = sin¹ (\frac{1 sin 0.120}{1.33}

       θ₁ = 0.090 rad

λ₂ = 600 nm

        θ₂ =sin⁻¹  \frac{1 sin 0.181}{1.33}

        θ₂ = 0.1358 rad

The angular separation is

          Δθ = 0.1358 - 0.090

          Δθ = 0.046 rad.

In conclusion using the relation for the diffraction grating we can find the results for the questions about angular separation are:

       i) The third order is Δθ = 0.203 rad.

      ii) The first order with water is Δθ = 0.046 rad.

Learn more here: brainly.com/question/473160

6 0
3 years ago
1.Una partícula de masa m = 0.2 [kg] está unido a dos resortes idénticos (de longitud L = 1.2 [m]) sobre la parte superior de un
uysha [10]

Answer:

walang kuwento

Explanation:

kasi ma answer ko

8 0
3 years ago
If Manuel exerts a force of 10 N to push a desk to the right at the same time Lynn exerts a force of 15 N to push the desk to th
wolverine [178]

Answer:

The desk will move to the left.

Explanation:

Since Manuel is exerting a force of 10 N to the right, and Lynn is exerting a force of 15 N to the left, it means that Lynn is exerting a force of 5 N more than Manuel, meaning that the desk will move to the left, the direction Lynn is pushing it too.

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3 0
3 years ago
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