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Delicious77 [7]
2 years ago
15

PLS HELPP ITS A TEST!!! I WILL GIVE BRAINLIEST!!!

Mathematics
2 answers:
nydimaria [60]2 years ago
5 0

Answer:

There is no picture.

Step-by-step explanation:

Lady bird [3.3K]2 years ago
5 0
Answer:



Either 1/10 or 9/10


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Find the product and simplify. (3c-5) ^2
RSB [31]

Answer:

9c² -30c + 25

Step-by-step explanation:

Perfect square trinomial: (a - b)² = a² - 2ab + b²

(3c - 5)²

(3c)² -2(3c * 5) + 5²

9c² -2(15c) + 5²

9c² -30c + 25

Final answer: 9c² -30c + 25

Hope this helps!

7 0
2 years ago
Read 2 more answers
Nine boys share 4 pizzas equally. what fraction of a pizza does each boy get?
Aleks04 [339]
Your answer would be 2 and 1/4 because when you divide 9 and 4 you get that. 
8 0
3 years ago
Read 2 more answers
What is the greatest possible product of a 2 digit number and a 1 digit number?? explain how u know
KIM [24]
To find the greatest possible product, you need the greatest possible numbers. The largest possible 2-digit number is 99. The largest possible 1-digit number is 9. Therefore, 99 * 9 will be the largest possible product under these circumstances.

99 * 9 = 891

Hope this helps! :)
4 0
3 years ago
In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T
dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + \frac{h^{2} }{2!}f''(a) = 0

h = \frac{-f'(a) }{f''(a)} ± \frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}

So, we get the succeeding equation for Newton's method as

x_{i+1} = x_{i} + \frac{1}{f''x_{i}}  [-f'(x_{i}) ± \sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]

Part B.

It is evident that Newton's method fails in two cases, as:

1.  if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)    

Part C.

In case  x_{i+1} is close to x_{i}, the choice that shouldbe made instead of ± in part A is:

f'(x) = \sqrt{f'(x)^{2} - 2f(x)f''(x)}  ⇔ x_{i+1} = x_{i}

Part D.

As given x_{i+1} = x_{i} = h

or                 h = x_{i+1} - x_{i}

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also,             (x_{i+1}-x_{i})² = -(x_{i+1}-x_{i})(f(x_{i})/f'(x_{i}))

So,                f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes   h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also,             x_{i+1} = x_{i} -f(x_{i})/f'(x_{i}) + [(x_{i+1} - x_{i})f''(x_{i})f(x_{i})]/[2(f'(x_{i}))²]

6 0
3 years ago
Let h = number of hours to bike 165 mi. Let m = number of miles biked in 7 hr. Which proportion can be used to determine the val
Drupady [299]

Answer:

\frac{m}{h}  =  \frac{165}{7}

5 0
1 year ago
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