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BigorU [14]
3 years ago
6

"three points A, B, and C are collinear, and B is between A and C, then AB + BC = AC” is a statement of the ___ postulate

Chemistry
1 answer:
olchik [2.2K]3 years ago
4 0
Segment addition postulate.
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2NOCl(g) ↔ 2NO(g) + Cl2(g) with K = 1.6 x10–5. In an experiment, 1.00 mole of pure NOCl and 1.00 mole of pure Cl2 are placed in
poizon [28]

Answer: 3.8\times 10^{-3}M

Explanation:

Moles of  NOCl = 1 mole

Moles of  Cl_2 = 1 mole

Volume of solution = 1 L

Initial concentration of NOCl = 1 M

Initial concentration of Cl_2 = 1 M

The given balanced equilibrium reaction is,

                  2NOCl(g)\rightleftharpoons 2NO(g)+Cl_2(g)

Initial conc.          1 M                      0M          1 M

At eqm. conc.     (1-2x) M              (2x) M       (1+x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[NO]^2[Cl_2]}{[NOCl]^2}

The K_c= 1.6\times 10^{-5}}

Now put all the given values in this expression, we get :

{1.6\times 10^{-5}}=\frac{(2x)^2\times (1+x)}{(1-2x)^2}

By solving the term 'x', we get :

x=0.0019

Concentration of NO at equilibrium= (2x) M  =  2\times 0.0019=3.8\times 10^{-3}M

6 0
2 years ago
A neutron has a positive electrical charge.<br> True or false
liberstina [14]
A neutron has neither a negative or positive charge, it’s neutral
3 0
3 years ago
Read 2 more answers
Which element exhibits a crystalline<br> structure at STP?<br> 1)F<br> 2)CI<br> 3)Br<br> 4) I
umka21 [38]
It would be F only because I wouldn’t make sense CI doesn’t exhibit crystalline neither does BR so F
6 0
3 years ago
A radioactive element reduces to 5.00% of its initial mass in
Stolb23 [73]

The half-life in months of a radioactive element that reduce to 5.00% of its initial mass in 500.0 years is approximately 1389 months

To solve this question, we'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:

Amount remaining (N) = 5%

Original amount (N₀) = 100%

<h3>Number of half-lives (n) =?</h3>

N₀ × 2ⁿ = N  

5 × 2ⁿ = 100

2ⁿ = 100/5

2ⁿ = 20

Take the log of both side

Log 2ⁿ = log 20

nlog 2 = log 20

Divide both side by log 2

n = log 20 / log 2

<h3>n = 4.32</h3>

Thus, 4.32 half-lives gas elapsed.

Finally, we shall determine the half-life of the element. This can be obtained as follow.

Number of half-lives (n) = 4.32

Time (t) = 500 years

<h3>Half-life (t½) =? </h3>

t½ = t / n

t½ = 500 / 4.32

t½ = 115.74 years

Multiply by 12 to express in months

t½ = 115.74 × 12

<h3>t½ ≈ 1389 months </h3>

Therefore, the half-life of the radioactive element in months is approximately 1389 months

Learn more: brainly.com/question/24868345

8 0
2 years ago
Is know as a force that pulls an object weight to center of the earth
vlabodo [156]

That force would be gravity.  Gravity is what pulls any object down towards Earth due to the large mass of the Earth.

4 0
3 years ago
Read 2 more answers
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