Answer: 
Explanation:
Moles of 
= 1 mole
Moles of 
= 1 mole
Volume of solution = 1 L
Initial concentration of = 1 M
Initial concentration of = 1 M
The given balanced equilibrium reaction is,
Initial conc. 1 M 0M 1 M
At eqm. conc. (1-2x) M (2x) M (1+x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[NO]^2[Cl_2]}{[NOCl]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO%5D%5E2%5BCl_2%5D%7D%7B%5BNOCl%5D%5E2%7D)
The 
= 
Now put all the given values in this expression, we get :
By solving the term 'x', we get :
Concentration of 
at equilibrium= (2x) M = 
A neutron has neither a negative or positive charge, it’s neutral
It would be F only because I wouldn’t make sense CI doesn’t exhibit crystalline neither does BR so F
The half-life in months of a radioactive element that reduce to 5.00% of its initial mass in 500.0 years is approximately 1389 months
To solve this question, we'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:
Amount remaining (N) = 5%
Original amount (N₀) = 100%
<h3>Number of half-lives (n) =?</h3>
N₀ × 2ⁿ = N
5 × 2ⁿ = 100
2ⁿ = 100/5
2ⁿ = 20
Take the log of both side
Log 2ⁿ = log 20
nlog 2 = log 20
Divide both side by log 2
n = log 20 / log 2
<h3>n = 4.32</h3>
Thus, 4.32 half-lives gas elapsed.
Finally, we shall determine the half-life of the element. This can be obtained as follow.
Number of half-lives (n) = 4.32
Time (t) = 500 years
<h3>Half-life (t½) =? </h3>
t½ = t / n
t½ = 500 / 4.32
t½ = 115.74 years
Multiply by 12 to express in months
t½ = 115.74 × 12
<h3>t½ ≈ 1389 months </h3>
Therefore, the half-life of the radioactive element in months is approximately 1389 months
Learn more: brainly.com/question/24868345
That force would be gravity. Gravity is what pulls any object down towards Earth due to the large mass of the Earth.
