All categories

2 years ago

The pressure of nitrogen gast at 35°C is changed from 0.89 atm to 4.3 atm. What will be its final temperature in Kelvin?

Chemistry

2 answers:

MA_775_DIABLO [31]2 years ago

8 0

Answer:

0.75 ATM. first option

SVETLANKA909090 [29]2 years ago

7 0

0.76 ATM i guess :///

You might be interested in

Write the chemical equations for the neutralization reactions that occurred when hcl and naoh were added to the buffer solution.

irga5000 [103]

A base and an Acid always react to form a salt and water

So, HCl + NaOH —> NaCl + HOH

5 0

2 years ago

What amount of carbon dioxide (in moles) is produced from the reaction of 2.24 moles of ethanol with excess oxygen?

algol13

Answer : The amount of carbon dioxide produced is, 197.12 grams.

Explanation : Given,

Moles of ethanol = 2.24 mole

Molar mass of carbon dioxide = 44 g/mole

The balanced chemical reaction will be,

$C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O$

First we have to calculate the moles carbon dioxide.

From the balanced chemical reaction, we conclude that

As, 1 mole of ethanol react to give 2 moles of carbon dioxide

So, 2.24 mole of ethanol react to give $2\times 2.24=4.48$ moles of carbon dioxide

Now we have to calculate the mass of carbon dioxide.

$\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass of }CO_2$

$\text{Mass of }CO_2=4.48mole\times 44g/mole=197.12g$

Therefore, the amount of carbon dioxide produced is 197.12 grams.

8 0

2 years ago

4. milk turning sour

sp2606 [1]

I think it’s a physical

7 0

2 years ago

Read 2 more answers

All organelles need energy to function which cell organelle provides the energy?

andre [41]

Ubnkariotic, mate. not Chloroplast

6 0

3 years ago

Read 2 more answers

The combustion reaction of isopropyl alcohol is given below: C 3 H 7 O H ( l ) + 9 2 O 2 ( g ) → 3 C O 2 ( g ) + 4 H 2 O ( g ) T

jek_recluse [69]

Answer:

the heat of formation of isopropyl alcohol is -317.82 kJ/mol

Explanation:

The heat of combustion of isopropyl alcohol is given as follows;

C₃H₇OH (l) +(9/2)O₂ → 3CO₂(g) + 4H₂O (g)

The heat of combustion of CO₂ and H₂O are given as follows

C (s) + O₂ (g) → CO₂(g) = −393.50 kJ

H₂ (g) + 1/2·O₂(g) → H₂O (l) = −285.83 kJ

Therefore we have

3CO₂(g) + 4H₂O (g) → C₃H₇OH (l) +(9/2)O₂ which we can write as

3C (s) + 3O₂ (g) → 3CO₂(g) = −393.50 kJ × 3 =

4H₂ (g) + 2·O₂(g) → 4H₂O (l) = −285.83 kJ × 4

3CO₂(g) + 4H₂O (g) → C₃H₇OH (l) +(9/2)O₂ = +2006 kJ/mol

-1180.5 - 1143.32 +2006 = -317.82 kJ/mol

Therefore, the heat of formation of isopropyl alcohol = -317.82 kJ/mol.

3 0

3 years ago