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3 years ago

The radius of a circle is 12.1 ft. Find the circumference to the nearest tenth}to the nearest tenth

Mathematics

2 answers:

e-lub [12.9K]3 years ago

4 0

Answer:

<h2>Given :-</h2>

Radius of circle = 12.1 ft

Circumference

<h2>Solution :- </h2>

As we know that

$\boxed { \bf \: Circumference = 2\pi \: r}$

$\tt \: C = 2 \times \dfrac{22}{7} \times 12.1$

$\tt \: C = \dfrac{44}{7} \times 12.1$

$\huge \bf \pink{C = 76.0}$

Gnoma [55]3 years ago

3 0

Answer:

76 ft

Step-by-step explanation:

Use the circumference formula, C = 2 $\pi$ r

Plug in the radius:

C = 2 $\pi$ r

C = 2 $\pi$ (12.1)

C = 76.0

So, the circumference is 76 ft

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3 years ago

Assume the general population gets an average of 7 hours of sleep per night. You randomly select 45 college students and survey

tekilochka [14]

Answer:

a) ii. This is a left-tailed test.

b) -1.59

c) -1.301

d) i. reject null hypothesis

e) Option i) The data supports the claim that college students get less sleep than the general population.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 7 hours

Sample mean, $\bar{x}$ = 6.87 hours

Sample size, n = 45

Alpha, α = 0.10

Sample standard deviation, s = 0.55 hours

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 7\text{ hours}\\H_A: \mu < 7\text{ hours}$

a) We use one-tailed(left) t test to perform this hypothesis.

b) Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{6.87 - 7}{\frac{0.55}{\sqrt{45}} } =-1.59$

c) Now,

$t_{critical} \text{ at 0.10 level of significance, 44 degree of freedom } = -1.301$

Since,

$t_{stat} < t_{critical}$

d) We fail to accept the null hypothesis and reject it.

We accept the alternate hypothesis and conclude that mean number of hours of sleep for all college students is less than 7 hours.

e) Option i) The data supports the claim that college students get less sleep than the general population.

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3 years ago

The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 1 2 3 4 . A rot

MaRussiya [10]

I found the corresponding image. Pls. see attachment.

The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 2 (translation and rotation).

A rotation translation must be used to make the two polygons coincide.

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