Answer:
The ratio of the forces is F2/F1 = 1.86
Explanation:
From Newton's second law applied to circular motion, the total force F acting on a body in circular motion is given by
F = mv²/r
Where
m = mass of the body undergoing circular motion
v = linear velocity = ω×r
ω = angular velocity
r = radius of the circular path through which the force acts
So
F = m(ω×r)²/r = mω²×r
Given 2 angular speeds ω1 = 439re/min = 439×2π/60 rad/s = 46 rad/s and
ω2 = 602rev/min = 602×2π/60 rad/s = 63 rad/s
Required to calculate the ratio F2/F1
The mass m and radius r is the same for both forces, so F is dependent on the angular speed
So F2/F1 = ω2²/ω1² = (ω2/ω1)²
F2/F1 = (63/46)² = 1.86
It is natural gases hope this helps
Answer:
85.9 V
Explanation:
The voltage across C₃ is 40.0 V, so the voltage between a and d must also be 40.0 V.
Find the equivalent capacitance of C₁, C₂, and C₃:
C₁₂₃ = 1 / (1/C₁ + 1/C₂) + C₃
C₁₂₃ = 1 / (1/8.00 + 1/7.00) + 2.00
C₁₂₃ = 5.73 mF
This is in series with C₄. Capacitors in series have the same charge, so:
Vad C₁₂₃ = Vbd C₄
(40.0) (5.73) = Vbd (5.00)
Vbd = 45.9 V
The total voltage is therefore:
V = Vad + Vbd
V = 40.0 + 45.9
V = 85.9 V
Fnet = Fg sin 30 - Ff
ma = mg sin 30 - mew Fg cos 30
ma = mg sin 30 - mew mg cos 30
a = g sin 30 - mew gcos30
a - g sin 30 = - mew g cos 30
mew = -(a - g sin30)/(g cos 30)
mew = -(3m/s2 - 9.81sin30)/(9.81 cos 30)
mew = 0.22
Answer:
7.08 m
Explanation:
(If we ignore the refraction of light)
There will form two triangles one at the top of pool (torch, edge of pool and point of incidence at top of pool) and one at the bottom of pool (torch, edge of pool and point of incidence at bottom of pool) .
first triangle at the top of pool (torch, edge of pool and point of incidence at top of pool)
First we need to find the angle of incidence:
Height = perpendicular = 1.3 m
Point of incidence = base= 2.5 m
now
tan∅= perpendicular / base
∅= tan⁻¹ (perpendicular / base)
∅=tan⁻¹ (1.3/2.5)
∅= 27.5°
Now 2nd triangle at the bottom of pool (torch, edge of pool and point of incidence at bottom of pool)
Height = perpendicular = 1.3 m + 2.1 m= 3.4 m (torch height + depth of pool)
∅= 27.5°
Spot of light hit bottom of pool= base=?
tan∅ = perpendicular / base
base = perpendicular / tan∅
base = 3.4/tan(27.5°)
base= 7.08 m
Spot of light hit bottom of pool= base= 7.08 m