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DaniilM [7]
2 years ago
5

SOMEONE PLEASE HELP MEEEEEEE

Physics
1 answer:
julia-pushkina [17]2 years ago
8 0

Answer:

The movement of Tectonic plates.

Explanation:

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A bus moving along a level road increases its speed from 20 m/s to 35 m/s in 15.0s. What is the car's acceleration?​
Ksju [112]

Explanation:

initial velocity U = 20m/s

Final velocity V = 35m/s

time = 15.0 secs

change in velocity = 35 - 15

= 20m/s

acceleration a = change in velocity/time V/t

a = (35-20)/15

a= 15/15

Hence, your acceleration is 1m/s^2

5 0
2 years ago
Compared to the charge on a proton, the amount of charge on an electron is,
lbvjy [14]
Compared to the charge on a proton, the amount of charge on an electron is same and has the opposite sign
3 0
3 years ago
What is the potential energy of a 2 kg ball 15 m in the air?
oee [108]

Answer:

<h2>300 J</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 2 × 10 × 15

We have the final answer as

<h3>300 J</h3>

Hope this helps you

7 0
3 years ago
I wish to use a step up transformer to turn an initial RMS AC voltage of 100 V into a final RMS AC voltage of 200 V. What is the
zhuklara [117]

Answer:

1:2

Explanation:

It is given that,

Initial RMS AC voltage is 100 V and final RMS AC voltage is 200 V.

We need to find the ratio of the number of turns in the primary to the secondary  for step up transformer.

For a transformer, \dfrac{V_1}{V_2}=\dfrac{N_1}{N_2}

So,

\dfrac{N_1}{N_2}=\dfrac{100}{200}\\\\\dfrac{N_1}{N_2}=\dfrac{1}{2}

So, the ratio of the number of turns in the primary to the secondary is 1:2.

4 0
3 years ago
If an isotope has 8 protons and 10 neutrons in it's nucleus, what is it's atomic mass?
viva [34]
The atomic mass is always equal to the sum of protons and neutrons in the nucleus. If you add the number of protons and neutrons (8 + 10) = 18 you will find that the atomic mass is 18.
8 0
3 years ago
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