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DaniilM [7]
3 years ago
5

SOMEONE PLEASE HELP MEEEEEEE

Physics
1 answer:
julia-pushkina [17]3 years ago
8 0

Answer:

The movement of Tectonic plates.

Explanation:

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A 60 year old person has a threshold of hearing of 95.0 dB for a sound with frequency f=10,000 Hz. By what factor must the inten
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Answer:

The intensity increased by a factor of 158489

Explanation:

Given that,

Sound level = 95.0 dB

Sound level = 43.0 dB

Frequency = 10000 Hz

We need to calculate the ratio of sound intensity

Using formula of sound level

sound\ level =10 log\dfrac{I}{I_{0}}

Put the value into the formula

95.0=10\ log\dfrac{I_{1}}{I_{0}}...(I)

43.0=10\ log\dfrac{I_{2}}{I_{0}}.....(II)

Subtracting these equations

52.0=10\ log\dfrac{I_{1}}{I_{2}}

\log\dfrac{I_{1}}{I_{2}}=5.2

Taking inverse log

\dfrac{I_{1}}{I_{2}}=10^{5.2}

\dfrac{I_{1}}{I_{2}}=158489

Hence, The intensity increased by a factor of 158489

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3 years ago
What is true about the inertia of two cars , car A of mass 1,500 kilograms and car B of mass 2,000 kilograms?
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Car B mass 2,000 kilograms
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Which condition is a neuron in when the outside of the neuron has a net positive charge and the inside has a net negative charge
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The membrane that surrounds a certain type of living cell has a surface area of 5.3 x 10-9 m2 and a thickness of 1.1 x 10-8 m. A
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Answer:

2.1\times 10^{-12} c

Explanation:

We are given that

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Thickness of membrane=1.1\times 10^{-8} m

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We have to find the charge resides on the outer surface of membrane.

Capacitance between parallel plate capacitor is given by

C=\frac{k\epsilon_0 A}{d}

Substitute the values then we get

Capacitance between parallel plate capacitor=\frac{5.9\times 8.85\times 10^{-12}\times 5.3\times 10^{-9}}{1.1\times 10^{-8}}

C=0.25\times 10^{-12}F

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Q=CV

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Hence, the charge resides on the outer surface=2.1\times 10^{-12} c

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