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Gemiola [76]
3 years ago
11

The spin cycles of a washing machine have two angular speeds, 439 rev/min and 602 rev/min . The internal diameter of the drum is

0.500 m . Part A What is the ratio of the maximum radial force on the laundry for the higher angular speed to that for the lower speed
Physics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

The ratio of the forces is F2/F1 = 1.86

Explanation:

From Newton's second law applied to circular motion, the total force F acting on a body in circular motion is given by

F = mv²/r

Where

m = mass of the body undergoing circular motion

v = linear velocity = ω×r

ω = angular velocity

r = radius of the circular path through which the force acts

So

F = m(ω×r)²/r = mω²×r

Given 2 angular speeds ω1 = 439re/min = 439×2π/60 rad/s = 46 rad/s and

ω2 = 602rev/min = 602×2π/60 rad/s = 63 rad/s

Required to calculate the ratio F2/F1

The mass m and radius r is the same for both forces, so F is dependent on the angular speed

So F2/F1 = ω2²/ω1² = (ω2/ω1)²

F2/F1 = (63/46)² = 1.86

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Answer:

The magnitude of the force between the two parallel wires is 0.0111 N.

Explanation:

Given;

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distance between the two wires, r = 0.03 m

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Therefore, the magnitude of the repulsive force between the two parallel wires is given by;

F = \frac{\mu_0 I_1I_2l}{2\pi r}\\\\where;\\\mu_0 \ is \ permeability \ of \ free \ space = 4\pi *10^{-7} \ T.m/A \\\\F = \frac{(4\pi *10^{-7})(6.3)^2(42)}{2\pi (0.03)}\\\\F =   0.0111 \ N

Therefore, the magnitude of the force between the two parallel wires is 0.0111 N.

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3 years ago
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Ludmilka [50]

Answer:

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You push against a steamer trunk with a force of 800 n at an angle alpha with the horizontal . the trunk is on a flat floor and
galina1969 [7]
The formula for this problem that we will be using is:
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I’m not sure but I think this is it!

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A point charge q1=+5.00nC is at the fixed position x=0, y=0, z=0. You find that you must do 8.10×10−6J of work to bring a second
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The value of the second charge is 1.2 nC.

<h3>Electric potential</h3>

The work done in moving the charge from infinity to the given position is calculated as follows;

W = Eq₂

E = W/q₂

<h3>Magnitude of second charge</h3>

The magnitude of the second charge is determined by applying Coulomb's law.

E = \frac{kq_2}{r^2} \\\\\frac{kq_2}{r^2} = \frac{W}{q_2} \\\\kq_2^2 = Wr^2\\\\q_2^2 = \frac{Wr^2}{k} \\\\q_2 = \sqrt{\frac{Wr^2}{k} } \\\\q_2 =  \sqrt{\frac{(8.1 \times 10^{-6}) \times (0.04)^2}{9\times 10^9} } \\\\q_2 = 1.2 \times 10^{-9} \ C\\\\q_2 = 1.2 \ nC

Thus, the  value of the second charge is 1.2 nC.

Learn more about electric potential here: brainly.com/question/14306881

7 0
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