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Tanzania [10]
3 years ago
9

Please help it’s due very soon and this is my last attempt !!

Physics
1 answer:
Scilla [17]3 years ago
8 0

Answer:

85.9 V

Explanation:

The voltage across C₃ is 40.0 V, so the voltage between a and d must also be 40.0 V.

Find the equivalent capacitance of C₁, C₂, and C₃:

C₁₂₃ = 1 / (1/C₁ + 1/C₂) + C₃

C₁₂₃ = 1 / (1/8.00 + 1/7.00) + 2.00

C₁₂₃ = 5.73 mF

This is in series with C₄.  Capacitors in series have the same charge, so:

Vad C₁₂₃ = Vbd C₄

(40.0) (5.73) = Vbd (5.00)

Vbd = 45.9 V

The total voltage is therefore:

V = Vad + Vbd

V = 40.0 + 45.9

V = 85.9 V

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Answer:

E) True. The girl has a larger tangential acceleration than the boy.

Explanation:

In this exercise they do not ask us to say which statement is correct, for this we propose the solution to the problem.

Angular and linear quantities are related

          v = w r

          a = α r

the boy's radius is r₁ = 1.2m the girl's radius is r₂ = 1.8m

as the merry-go-round rotates at a constant angular velocity this is the same for both, but the tangential velocity is different

          v₁ = w 1,2 (boy)

          v₂ = w 1.8 (girl)

whereby

          v₂> v₁

reviewing the claims we have

          a₁ = α 1,2

          a₂ = α 1.8

          a₂> a₁

A) False. Tangential velocity is different from zero

B) False angular acceleration is the same for both

C) False. It is the opposite, according to the previous analysis

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3 years ago
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You pull on a crate using a rope as in (Figure 1), except the rope is at an angle of 20.0 ∘ above the horizontal. The weight of
Nezavi [6.7K]

Hi there!

For an object on an incline with friction being pulled, the following forces are present.

  • Force due to Gravity
  • Force due to Friction
  • Force due to tension

The force due to friction opposes the force due to gravity which would cause the object to slide down. (The force due to friction acts up the incline). Additionally, the force due to the rope is also upward.

Let up the incline be positive, and down the incline be negative.

Doing a summation of forces:
\Sigma F = F_T + F_f - F_g

For the crate to be moving at a constant velocity, there is NO net force acting on the crate, so:
0 = F_T + F_f - F_g

Now, we can express each force as an equation.

Force due to tension:

  • Must be solved for.

Force due to gravity:

  • On an incline, this is equivalent to the SINE component of its weight.  (Force of gravity is STILL THE WEIGHT, but on an incline, it contains a horizontal component that contributes to the net force)

This is expressed as:
F_g = Mgsin\theta

Force due to friction:

  • Equivalent to the normal force and coefficient of friction. The normal force is the VERTICAL component of the object's weight, so:

N = Mgcos\theta

F_f = \mu Mgcos\theta

Now, plug these expressions into the above equation.

0 = F_T + \mu Mgcos\theta - Mgsin\theta\\\\Mgsin\theta - \mu Mgcos\theta = F_T

Mg = 245 N (weight). Plug in all values:
245sin(20) - 0.270(245)cos(20) = F_T\\\\F_T = \boxed{21.634 N}

The normal force is equivalent to the vertical component (PERPENDICULAR TO THE INCLINE) of the weight (cosine), so:

N = Mgcos\theta\\\\N = 245cos(20) = \boxed{230.225 N}

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dimulka [17.4K]

Answer:

The wavelength of the light is 633 nm.

Explanation:

Given that,

Distance between the two slits d= 0.025 cm

Distance between the screen and slits D = 120 cm

Distance between the slits y= 1.52 cm

We need to calculate the angle

Using formula of double slit

\tan\theta=\dfrac{y}{D}

Where, y = Distance between the slits

D = Distance between the screen and slits

Put the value into the formula

\tan\theta=\dfrac{1.52}{120}

\theta=\tan^{-1}\dfrac{1.52}{120}

\theta=0.725

We need to calculate the wavelength

Using formula of wavelength

d\sin\theta=n\lambda

Put the value into the formula

0.025\times\sin0.725=5\times\lambda

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\lambda=633\ nm

Hence, The wavelength of the light is 633 nm.

4 0
3 years ago
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