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2 years ago

What is the difference between a chemical process and a physical process in chemistry?

Chemistry

1 answer:

docker41 [41]2 years ago

7 0

Answer & Explanation:

The difference between a physical reaction and a chemical reaction is composition. In a chemical reaction, there is a change in the composition of the substances in question; in a physical change there is a difference in the appearance, smell, or simple display of a sample of matter without a change in composition.

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Match the following descriptions with the correct polysaccharide, note if you answer any part of this question incorrectly a sig

Ad libitum [116K]

Answer:

Glycogen. Cellulose. Amylose. Cellulose. Amylopetin and Glycogen. Amylopetin and Cellulose.

Explanation:

Glycogen is the form that glucose is stored in human body.

Cellulose is the structural part of plant cell walls and human cannot digest it.

Amylose is the polysaccharide linked mainly by the the bonds of $\alpha$ 1,4 glycosidic.

Cellulose is an unbranched polysaccharide linked mainly by the bonds of $\beta$ 1,4 glycosidic.

Amylopetin and Glycogen are branched polysaccharides linked by the bonds of $\alpha$ 1,4 glycosidic and $\alpha$ 1,6 glycosidic.

Amylopetin and Cellulose are mainly stored in plants.

4 0

3 years ago

A. Based on the activation energies and frequency factors, rank the following reactions from fastest to slowest reaction rate, a

deff fn [24]

Answer:

A) $E_{a} = 350KJ/mol$ , $E_{a} = 50KJ/mol$ , $E_{a} = 50KJ/mol$

A = 1.5× $10^{-7}s^{-1}$ , A = 1.9× $10^{-7} s^{-1}$ , A=1.5× $10^{-7} s^{-1}$

B) 4.469

Explanation:

From Arrhenius equation

$K=Ae^{\frac{E_{a} }{RT} }$

where; K = Rate of constant

A = Pre exponetial factor

$E_{a}$ = Activation Energy

R = Universal constant

T = Temperature in Kelvin

Given parameters:

$E_{a} =165KJ/mol$

$T_{1}=505K$

$T_{2}=525K$

$R=8.314JK^{-1}mol^{-1}$

taking logarithm on both sides of the equation we have;

$InK=InA-\frac{E_{a} }{RT}$

since we have the rate of two different temperature the equation can be derived as:

$In(\frac{K_{2} }{K_{1} } )=\frac{E_{a} }{R}(\frac{1}{T_{1} } -\frac{1}{T_{2} } )$

$In(\frac{K_{2} }{K_{1} } )=\frac{165000J/mol}{8.314JK^{-1}mol^{-1} }.(\frac{1}{505} -\frac{1}{525} )$

$In(\frac{K_{2} }{K_{1} } )$ = 19846.04×7.544× $10^{-5}$ = 1.497

$\frac{K_{2} }{K_{1} }$ = $e^{1.497}$ = 4.469

6 0

2 years ago

What do you think would happen to a light bulb in the open circuit?

densk [106]

Is there choices to this question? cant answer it without choices

6 0

2 years ago

Read the given expression. X = number of protons − number of core electrons Which of the following explains the identity of X an

shepuryov [24]

<u>Answer: </u>The correct statement is X is the effective nuclear charge, and it increases across a period.

<u>Explanation:</u>

We are given that:

X = number of protons − number of core electrons

Effective nuclear charge is defined as the actual nuclear charge (Z = number of protons) minus the screening effect caused by the electrons present between nucleus and valence electrons. These electrons are the core electrons.

The formula used for the calculation of effective nuclear charge given by Slater is:

$Z^*=Z-\sigma$

where,

$Z^*$ = effective nuclear charge

Z = atomic number or actual nuclear charge or number of protons

$\sigma$ = Screening constant

The effective nuclear charge increases as we go from left to right in a period because nuclear charge increases with no effective increase in screening constant.

Hence, the correct answer is X is the effective nuclear charge, and it increases across a period.

5 0

3 years ago

In two or more complete sentences, describe the process of fractional distillation that used to refine crude oil.

Oksi-84 [34.3K]

I hope this helps you

3 0

3 years ago

Read 2 more answers