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saul85 [17]
3 years ago
14

Kumar is producing the photoelectric effect by using red light. He wants to increase the energy of emitted electrons. Based on t

he research of Albert Einstein, what is the best way for him to do this?
Chemistry
2 answers:
Softa [21]3 years ago
7 0

Explanation:

Photoelectric effect: Electrons are ejected out from the surface of metal when light of sufficient frequency falls upon shiny surface of metals. light is made up small bundles of energy packets named photons which when falls on surface transfer their energy to electrons due which electrons ejects out of the metallic surface. The energy for one photon was given by expression:

E=h\nu, or E\propto \nu

h=Planck's constant, \nu= frequency of the light

Kumar can increase the energy of emitted electron by using light with higher value of frequency than the frequency of red light. This is because the energy  carried by the photon of a light is directly proportional to the frequency of the light. Higher the value of frequency of light higher will be the value of energy of a photon. And photon with higher energy will impart more amount of energy to an electron while ejection.

aliya0001 [1]3 years ago
3 0
He has to use a different colored light at a higher frequency.
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A certain object has a volume of 25.0 mL and a mass of 100 g. What is the density of the object?
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What causes eclipses? select three options
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The first, second, and 4th option

Explanation:

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2 years ago
A sample of carbon dioxide gas has a density of g/L at a pressure of 0.889 atm and a temperature of 55.0 °C. Assume ideal behavi
gladu [14]

Answer:

163.5 °C

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 686 mL.

Initial temperature (T1) = 55 °C.

Final volume (V2) = 913 mL

Initial pressure (P1) = final pressure (P2) = 0.889 atm

Final temperature (T2) =.?

Next, we shall convert celsius temperature to Kelvin temperature.

This can be done as shown below:

Temperature (K) = Temperature (°C) + 273

T(K) = T (°C) + 273

Initial temperature (T1) = 55 °C.

Initial temperature (T1) = 55 °C + 273

Initial temperature (T1) = 328 K

Next, we shall determine the new temperature of the gas.

Since the pressure is constant, we shall determine the new temperature as follow:

V1/T1 = V2 /T2

Initial volume (V1) = 686 mL.

Final volume (V2) = 913 mL

Initial temperature (T1) = 328 K

Final temperature (T2) =.?

V1/T1 = V2 /T2

686/328 = 913/T2

Cross multiply

686 x T2 = 328 x 913

Divide both side by 686

T2 = (328 x 913)/686

T2 = 436.5 K

Finally, we shall convert Kelvin temperature to celsius temperature.

This can be done as shown below:

Temperature (°C) = Temperature (K) – 273

T (°C) = T(K) – 273

T(K) = 436.5 K

T (°C) = 436.5 – 273

T (°C) = 163.5 °C

Therefore, the temperature of the gas sample is 163.5 °C.

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3 years ago
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