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4 years ago

7

Lets say I have I have an apartment that is 680 square ft. I need to figure out how many bananas can fit inside this apartment.

The average banana is length is 7 inches. The average width is 1.5 inches. So just like how many bananas can fit inside the apartment?

1 answer:

Sergeeva-Olga [200]4 years ago

7 0

Answer:

100 bananas????

Step-by-step explanation: that's to many bananas

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How many times longer I s on be mile that one foot

pychu [463]

Answer:

5,280 times

hope this helps

have a good day :)

Step-by-step explanation:

3 0

3 years ago

Solve the following equation.

elena-14-01-66 [18.8K]

Answer:

x=6

Step-by-step explanation:

x + 6 = x + x original problem

x + 6 = 2x combine like terms

-x = -x subtract x from both sides to have like terms on each side

6 = x solution

8 0

3 years ago

A waterslide is rented at $500 per day plus a charge per hour of use. The bounce house was used for 5 hours one day, and the tot

Mazyrski [523]

Answer: $500+5x=800$

Step-by-step explanation:

Given: The rent of waterslide per day = $500

Let x be the a charge per hour of use.

The number of hours bounce house was used = 5 hours

Since, the total charge was $800.

Therefore, the equation can be used to find the charge x, in dollars, per hour of use is given by :-

Fixed charge+5 times x=Total charge

$\Rightarrow500+5x=800$

4 0

3 years ago

Read 2 more answers

Alternate Interior Angles Theorem a. b. c. Corresponding Angles Flow Proof a. b. c. d. e. Proof Diagram a. b. c.

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

(1). m∠5 = 40° → (a) Given

m∠2 = 140° → (b) Given

∠5 and ∠2 are supplementary angles → (c) Interior angles on the same side of the transversal.

∠5 and ∠2 are the same side interior angles → (d) Both angles are supplementary

a║b → (e) By interior angles theorem of the parallel lines.

(2). Statements Reasons

1. l║n 1. Given

2. ∠2 ≅ ∠6 2. Corresponding angles

3. ∠4 ≅ ∠2 3. Vertical angles

4. ∠6 ≅ ∠4 4. Transitive property of equality

(3). Statements Reasons

1. ∠1 ≅ ∠5 1. Given

2. ∠4 ≅ ∠1 2. Vertical angles

3. ∠4 ≅ ∠5 3. Alternate interior angles

4. p║r 4. Definition of parallel lines

4 0

3 years ago

Will mark brainliest!!!plz helppp

muminat

Answer:

(5,-6)

Step-by-step explanation:

ONE WAY:

If $f(x)=x^2-6x+3$ , then $f(x-2)=(x-2)^2-6(x-2)+3$ .

Let's simplify that.

Distribute with $-6(x-2)$ :

$f(x-2)=(x-2)^2-6x+12+3$

Combine the end like terms $12+3$ :

$f(x-2)=(x-2)^2-6x+15$

Use $(x-b)^2=x^2-2bx+b^2$ identity for $(x-2)^2$ :

$f(x-2)=x^2-4x+4-6x+15$

Combine like terms $-4x-6x$ and $4+15$ :

$f(x-2)=x^2-10x+19$

We are given $g(x)=f(x-2)$ .

So we have that $g(x)=x^2-10x+19$ .

The vertex happens at $x=\frac{-b}{2a}$ .

Compare $x^2-10x+19$ to $ax^2+bx+c$ to determine $a,b,\text{ and } c$ .

$a=1$

$b=-10$

$c=19$

Let's plug it in.

$\frac{-b}{2a}$

$\frac{-(-10)}{2(1)}$

$\frac{10}{2}$

$5$

So the $x-$ coordinate is 5.

Let's find the corresponding $y-$ coordinate by evaluating our expression named $g$ at $x=5$ :

$5^2-10(5)+19$

$25-50+19$

$-25+19$

$-6$

So the ordered pair of the vertex is (5,-6).

ANOTHER WAY:

The vertex form of a quadratic is $a(x-h)^2+k$ where the vertex is $(h,k)$ .

Let's put $f$ into this form.

We are given $f(x)=x^2-6x+3$ .

We will need to complete the square.

I like to use the identity $x^2+kx+(\frac{k}{2})^2=(x+\frac{k}{2})^2$ .

So If you add something in, you will have to take it out (and vice versa).

$x^2-6x+3$

$x^2-6x+(\frac{6}{2})^2+3-(\frac{6}{2})^2$

$(x+\frac{-6}{2})^2+3-3^2$

$(x+-3)^2+3-9$

$(x-3)^2+-6$

So we have in vertex form $f$ is:

$f(x)=(x-3)^2+-6$ .

The vertex is (3,-6).

So if we are dealing with the function $g(x)=f(x-2)$ .

This means we are going to move the vertex of $f$ right 2 units to figure out the vertex of $g$ which puts us at (3+2,-6)=(5,-6).

The $y-$ coordinate was not effected here because we were only moving horizontally not up/down.

3 0

3 years ago