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blondinia [14]
3 years ago
14

A pulley system has an efficiency of 65.1%. If you perform 350 J of work, how much useful work does the pulley perform?

Physics
1 answer:
antoniya [11.8K]3 years ago
8 0

This is how its done!

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A closed flat loop conductor with radius 2mm is located in a changing uniform magnetic field. If the emf induced in the loop is
BARSIC [14]

Answer:

Rate of magnetic field is 15923.668 T/sec

Explanation:

We have given radius of loop conductor r = 2 mm = 0.002 m

Induced emf = 2 volt

As the magnetic field and plane are perpendicular to each other so angle between magnetic field and area is 0°

Cross sectional area of the conductor is equal to A=\pi r^2

A=3.14\times 0.002^2=1.256\times 10^{-6}m^2

Induced emf is given by e=\frac{-d\Phi }{dt}=-A\frac{dB}{dt}

2=1.256\times 10^{-6}\times \frac{dB}{dt}

\frac{dB}{dt}=159235.668T/sec

6 0
3 years ago
What are flavonoids responsible ?
Travka [436]

Answer:

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6 0
3 years ago
WILL MARK BRAINLIEST
VladimirAG [237]

Answer:

no 2 A graph with the x axis labelled X and Y axis labelled Y

6 0
3 years ago
Which type of electromagnetic radiation has the highest frequency?
Likurg_2 [28]

Explanation:

As we know that relation between energy and wavelength is as follows.

                  E = \frac{hc}{\lambda}

This means that energy is inversely proportional to wavelength. So, more is the energy of an electromagnetic radiation less will be its wavelength.

Also,          f = \frac{c}{\lambda}

Hence, less will be the wavelength more will frequency of a radiation.

Gamma rays are the rays that have highest energy, small wavelength and highest frequency.

Thus, we can conclude that gamma rays are the electromagnetic radiation which has the highest frequency.

7 0
3 years ago
A rectangular barge 7 m long and 2 m wide floats in fresh water. How much will the barge sink when loaded with 600 kg of sand? S
Oxana [17]
You must apply Archimides' principle.

The barge will sink until the sum of the forces on it equals zero.

The two forces are the weight of the barge (with sand) and the buoyancy force, the force exerted by the liquid (fresh water) on the barge.

Then, weight of the barge with sand = m*g = 600 kg * g

Buoyancy force = density of the fluid * Volume of displaced fulid * g

Then, m*g = density of the fulid * Volume of displaced fluid * g

m*g = df * Vf * g

m = df*Vf => Vf = m/df = 600 kg / 1 000 kg/m^3 = 0.6 m^3

The volume of the displaced fluid equals the volume of the portion of the barge sinked, wich is the area of the rectangular base times the depth to which it sinked>

7m*2m*H = 0.6 m^3 => H = 0.6 m^3 /[14 m^2] = 0.043 m = 4.3 cm

Answer: 4.3 cm







3 0
3 years ago
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