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Anettt [7]
3 years ago
11

WILL MARK BRAINLIEST

Physics
1 answer:
VladimirAG [237]3 years ago
6 0

Answer:

no 2 A graph with the x axis labelled X and Y axis labelled Y

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Find the area under the standard normal curve between z=0.19 and z=2.18. round your answer to four decimal places, if necessary.
LiRa [457]

The area under the standard normal curve between z=0.19 and z=2.18 is,

P(0.19<z<2.18)= 0.4101

<h3>How can we calculate the area under the curve?</h3>

To calculate the The area under the standard normal curve  between z=0.19 and z=2.18, we are using two things,

<u>Step 1</u>: The formula,

P(0.19<z<2.18)= P(Z<2.18)- P(Z<0.19)

<u>Step 2</u>: The statistical values of the area under the curve we get from the picture.

Now we put the known values from the picture in the above formula, we get,

P(0.19<z<2.18)= P(Z<2.18)- P(Z<0.19)

Or, P(0.19<z<2.18)=  0.9854-0.5753

Or, P(0.19<z<2.18)=  0.4101

From the above calculation we can easily conclude that,

The area under the standard normal curve between z=0.19 and z=2.18 is,

P(0.19<z<2.18)= 0.4101

Learn more about the standard normal curve:

brainly.com/question/17088387

#SPJ4

5 0
2 years ago
QUIZZ <br><br>12 + 14 + 66 - 87
svet-max [94.6K]

12 + 14 + 66 - 87

26+66-87

92-87

5

6 0
3 years ago
Read 2 more answers
A 375-g stone hangs from a thin light string that is wrapped around the circumference of a pulley with a moment of inertia of 0.
Monica [59]

Answer:

The magnitude of the acceleration of the stone is 19.87 m/s²

Explanation:

Given;

mass of stone, m = 375 g = 0.375 kg

moment of inertia, I = 0.0125 kg.m²

radius of the pulley, r = 26 cm = 0.26 m

Torque generated by the pulley on the stone is given as;

τ = F x r = Iα

where;

F is applied force on the stone due to its weight

r is the radius of the pulley

I is moment of inertia

α is angular acceleration (rad/s²)

Force, F = mg = 0.375 x 9.8 = 3.675 N

Torque, τ = F x r

τ = 3.675 x 0.26

τ = 0.9555 N.m

τ = Iα

Angular acceleration, α = τ / I

α = 0.9555 / 0.0125

α = 76.44 rad/s²

Finally, determine linear acceleration, a,  in m/s²

a = αr

a = 76.44 x 0.26

a = 19.87 m/s²

Therefore, the magnitude of the acceleration of the stone is 19.87 m/s²

4 0
3 years ago
For years, the tallest tower in the United States was the Phoenix Shot Tower in Baltimore, Maryland. The shot tower was used fro
serious [3.7K]

Answer:

The answer to your question is:

a) t = 3.81 s

b) vf =  37.4 m/s

Explanation:

Data

height = 71.3 m = 234 feet

t = 0 m/s

vf = ?

vo = 0 m/s

Formula

h = vot + 1/2gt²

vf = vo + gt

Process

a)

               h = vot + 1/2gt²

             71.3 = 0t + 1/2(9.81)t²

             2(71.3) = 9,81t²

              t² = 2(71.3)/9.81

              t² = 14.53

              t = 3.81 s

b)

      vf = 0 + (9.81)(3.81)

      vf = 37.4 m/s

3 0
3 years ago
You are designing a hydraulic lift for a machine shop. the average mass of a car it needs to lift is about 1500 kg. you wish to
Alchen [17]
You want the force/area ratio to be the same for both pistons to keep constant pressure. Since 1500/450=3.333, you will need to pick the two sets of dimensions such that (assuming the pistons are rectangular) the product of the pair of dimensions for the 1500 kg piston is 3.333 times the product of the pair of dimensions for the 450 kg piston.
6 0
3 years ago
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