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egoroff_w [7]
3 years ago
7

How is photon energy calculated? (choose 2)

Physics
1 answer:
raketka [301]3 years ago
5 0
Using Placks’s constant and frequency
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Anyone know the answer to this, would kindly appreciate it
Ipatiy [6.2K]

Answer:

The found value of r is:

r = 94.7

Explanation:

We know that

cosθ = Base / Hypotenuse

θ is the always the angle between base and hypotenuse

In this right angles triangle, the angle θ is given 63°.

Which means that the Base is 43 and the hypotenuse is r

Base = 43

Hypotenuse = r

Substitute θ=63°, Base = 43 and hypotenuse = r in the formula of cosθ mentioned above:

cos 63° = 43/r

Rearrange

r = 43/cos63°

r = 43/0.454

r= 94.7

6 0
3 years ago
What is the resultant of the two vectors shown?
Ksju [112]

Answer

correct answer is C

Head-to-tail method

Here head-to-tail method is employed to determine resultant of vectors.

Let horizontal component be 1 and let vertical component be 2

To add these two vectors. Move vector 2 until its tail touches the head of 1. The tail of resultant of these two vectors touch the tail of vector 1 and head of resultant vector will touch the head of vector 2.

6 0
3 years ago
Read 2 more answers
A 12-bit analog to digital data acquisition module has an input range of 0 vdc to + 10 vdc. calculate the least significant bit
trasher [3.6K]

Correct answer is 2.441mV

What is Digital data?

Digital data is information represented as a string of discrete symbols, each of which can take on one of only a finite number of values from some alphabet, such as letters or digits, in information theory and information systems. s. Binary data is the most common type of digital data in modern information systems. It is represented by a string of binary digits (bits), each of which can have one of two values, 0 or 1.

In contrast to digital data, analog data is represented by a value from a continuous range of real numbers.

To learn more about Digital output from the given link:

https://brainly.in/question/2989269

#SPJ4

7 0
2 years ago
What are 2 ways organisms would be affected by water pollution?
Ymorist [56]
Not having clean water to drink or bath. Also some organizations that live in the water might die because the water is polluted and that would be toxic form them
7 0
4 years ago
At locations A and B, the electric potential has the values VA=1.51 VVA=1.51 V and VB=5.81 V,VB=5.81 V, respectively. A proton r
Oksana_A [137]

Answer:

<u>For proton:</u>

A. The proton is released from Vb (highest potential)

B. v = 2.9x10⁴ m/s

<u>For electron:</u>

A. The electron is released from Va (lowest potential)

B. v = 1.2x10⁶ m/s    

Explanation:

<u>For a proton we have</u>:

A. To find the origin from which the proton was released we need to remember that in a potential difference, a proton moves from the highest potential to the lowest potential.                

Having that:

Va = 1.51 V and Vb = 5.81 V

We can see that the proton moves from Vb to Va, hence the proton was released from Vb.

B. We now that the work done by an electric field is given by:

W = \Delta Vq    (1)                                        

Where:

q: is the proton's charge = 1.6x10⁻¹⁹ C    

V: is the potential    

Also, the work is equal to:

W = \Delta K = (K_{a} - K_{b}) = \frac{1}{2}mv_{a}^{2} - \frac{1}{2}mv_{b}^{2}     (2)      

Where:

K: is the kinetic energy

m: is the proton's mass = 1.67x10⁻²⁷ kg

v_{a}: is the velocity in the point a

v_{b}: is the velocity in the point b = 0 (starts from rest)

Matching equation (1) with (2) we have:

\Delta Vq = \frac{1}{2}mv_{a}^{2}

(5.81 V - 1.51 V)*1.6 \cdot 10^{-19} C = \frac{1}{2}1.67 \cdot 10^{-27} kg*v_{a}^{2}

v_{a} = 2.9 \cdot 10^{4} m/s

<u>For an electron we have</u>:

A. For an electron we know that it moves from the lowest potential (Va) to the highest potential (Vb), so it is released from Va.

B. The speed is:

\Delta Vq = \frac{1}{2}mv_{b}^{2} - \frac{1}{2}mv_{a}^{2}

Since v_{a} = 0 (starts from rest) and m_{e} = 9.1x10⁻³¹ kg (electron's mass), we have:

(5.81 V - 1.51 V)*1.6 \cdot 10^{-19} C = \frac{1}{2}9.1 \cdot 10^{-31} kg*v_{b}^{2}    

v_{b} = 1.2 \cdot 10^{6} m/s

I hope it helps you!

6 0
4 years ago
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