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3 years ago

13

Which type of electromagnetic radiation has the highest frequency?

1 answer:

Likurg_2 [28]3 years ago

7 0

Explanation:

As we know that relation between energy and wavelength is as follows.

E = $\frac{hc}{\lambda}$

This means that energy is inversely proportional to wavelength. So, more is the energy of an electromagnetic radiation less will be its wavelength.

Also, f = $\frac{c}{\lambda}$

Hence, less will be the wavelength more will frequency of a radiation.

Gamma rays are the rays that have highest energy, small wavelength and highest frequency.

Thus, we can conclude that gamma rays are the electromagnetic radiation which has the highest frequency.

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Two small frogs simultaneously leap straight up from a lily pad. Frog A leaps with an initial velocity of 0.551 m/s, while frog

goblinko [34]

Answer:

d = .076 m

Explanation:

The time for frog A can be calculated from equation of motion

$v_f = v_o + at$

where v_f is final velocity, a is acceleration due to gravity

so from given data we have

$-0.551= 0.551 + (-9.8)(t)$

t = 0.112 sec

Now we will use that time for frog B

$v_f = v_o + at$

$v_f = 1.23 + (-9.8)(0.112)$

$v_f = 0.128 m/s$ (Note its positive)

For the displacement

$s = v_o t + 0.5at^2$

$s = (1.23)(0.112) + (.5)(-9.8)(0.112)^2$

d = .076 m

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3 years ago

5. Alex goes cruising on his dirt bike. He rides 700 m north, 300 m east, 400 m north, 600 m west, 1200 m south 300 m east and f

Gala2k [10]

Answer:

Explanation:

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3 years ago

Dr. John Paul Stapp was U.S. Air Force officer who studied the effects of extreme deceleration on the human body. On December 10

Mars2501 [29]

Answer:

a) $a=5.7551 \times g$

b) $d=20.5539\times g$

Explanation:

Given:

speed of rocket initially, $v_i=0\ m.s^{-1}$

top speed of rocket after acceleration, $v=282\ m.s^{-1}$

time taken to get to the top speed, $t_i=5\ m.s^{-1}$

final speed of the rocket, $v_f=0\ m.s^{-1}$

time taken to get to the final speed after reaching the top speed, $t_f=1.4\ s$

Now the acceleration:

$a=\frac{v-v_i}{t_i}$

$a=\frac{282-0}{5}$

$a=56.4\ m.s^{-2}$

Now as a fraction of gravity:

$a=\frac{56.4}{9.8}\times g$

$a=5.7551 \times g$

Now, the deceleration:

$d=\frac{0-282}{1.4}$

$d=201.4285\ m.s^{-2}$

Now as a fraction of gravity:

$d=\frac{201.4285}{9.8}\times g$

$d=20.5539\times g$

6 0

4 years ago

The diameter of a 12-gauge copper wire is 0.081 in. The maximum safe current it can 17) carry (in order to prevent fire danger i

Soloha48 [4]

Answer:

0.44m/s

Explanation:

drift velocity=I/nAq

diameter 12 gauge

wire=0.081inches=0.081*2.5=0.2025cm radius=0.10125cm area=pi*R^2 =20/8.5*10^22*3.14*0.10125^2*10^-4*1.6*10^-19*

V = 0.44m/s

6 0

4 years ago

A 0.12-mu or micro FF capacitor, initially uncharged, is connected in series with a 10-kohm resistor and a 12-V battery of negli

miv72 [106K]

Answer:

The time is 2.8 ms.

Explanation:

Given that,

Capacitor = 0.12 μF

Resistance = 10 kohm

Voltage = 12 V

Charge Q = 0.9 Q₀

We need to calculate the time constant

Using formula of time constant

$T=RC$

Put the value into the formula

$T=10\times10^{3}\times0.12\times10^{-6}$

$T=0.0012\ sec$

We need to calculate the time

Using formula of time

$Q=Q_{0}(1-e^{\frac{-t}{T}})$

Put the value into the formula

$0.9Q_{0}=Q_{0}(1-e^{\frac{-t}{0.0012}})$

$ln (0.1)=\dfrac{-t}{0.0012}$

$t=0.00276\ sec$

$t=2.8\ ms$

Hence, The time is 2.8 ms.

6 0

4 years ago