The length of the smaller leg is 3.79
<h3>How to determine the length of the smaller leg?</h3>
Represent the smaller leg with x.
So, we have:
-- Pythagoras theorem
This gives
2x^2 = 144/5
Divide by 2
x^2 = 72/5
This gives
x^2 = 14.4
Take the square root
x = 3.79
Hence, the length of the smaller leg is 3.79
Read more about right triangles at
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1. x - 4
x - 6|x² - 10x + 24
- (x² - 6x)
-4x + 24
- (4x + 24)
0
The answer is C.
2. A. 9x² + 12x - 3
3(x²) + 3(4x) - 3(1)
3(x² + 4x - 1)
B. 9x² + 3x - 5
Not Factored
C. 6x² + 10x - 4
2(3x²) + 2(5x) - 2(2)
2(3x² + 5x - 2)
2(3x² + 6x - x - 2)
2(3x(x) + 3x(2) - 1(x) - 1(2))
2(3x(x + 2) - 1(x + 2))
2(3x - 1)(x + 2)
D. 6x² + 7x - 6
Not Factored
The answer is C.
3. 3x³ - 4x² + 3x - 6
x + 2|3x⁴ + 2x³ - 5x² + 0x - 4
- (3x⁴ + 6x³)
-4x³ - 5x²
- (-4x³ - 8x²)
3x² + 0x
- (3x² + 6x)
-6x - 4
- (-6x - 12)
8
The answer is A.
Given that the two swimmers competed and Ursula's speed is 60 m/min while Andre's speed is 48 m/min. The distance that the Ursula will catch up with Andre will be:
distance=(relative speed)×(time)
relative speed=60-48=12 m/min
the two swimmers met at a distance of:
12×1
=12 meters
Answer:
30 cm
Step-by-step explanation:
2 * 15: 5 * 15
30:75
