Question

How many aluminum atoms are in 3.78g of aluminum?

Answer 1

Answer:

The molar mass of aluminum is 26.9 grams per mole. We start by converting the grams of aluminum to moles of aluminum.

m

o

l

 

A

l

 

=

 

3.78

 

g

 

A

l

×

1

 

m

o

l

 

A

l

26.9

 

g

 

=

 

0.1405

 

m

o

l

 

A

l

We use Avogadro's number to determine the number of aluminum atoms present in 0.1405 mol Al.

A

t

o

m

s

 

A

l

 

=

 

0.1405

 

m

o

l

 

A

l

×

6.022

×

10

23

1

 

m

o

l

 

A

l

 

=

 

8.46

×

10

22

 

a

t

o

m

s

 

A

l

Answer 2

Answer:

0.846×10²³

Explanation:

molar mass of aluminum is 26.9 g/mol.  

converting the grams of aluminum to moles of aluminum.

mol Al = 3.78 g ×1 mol Al÷26.9 g = 0.1405 mol of Al

to determine the number of aluminum atoms present in 0.1405 mol Al we use the Avogrado's number which is equal to 6.022×10²³

Atoms of  Al = 0.1405 mol Al×6.022×10²³

= 0.846×10²³

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