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FrozenT [24]
3 years ago
12

In chemistry, what varies with the number of molecules present in a sample of a particular substance?

Chemistry
1 answer:
Neko [114]3 years ago
3 0

Answer: concentration

Explanation:

Concentration refers to the amount of a substance present in a sample. The more molecules of a substance present in a sample, the greater its concentration. The less molecules of a substance in a sample, the lesser the concentration. We are often concerned about analytically determining the concentration of a substance using diverse analytical methods in chemistry.

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A solid sample of a compound and a liquid sample of the same compound are each tested for electrical conductivity. Which test co
BigorU [14]

Answer:

i have no idea

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Explanation:

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What are tidal conditions in science terms
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They are the tides and conditions of the oceans
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3 years ago
Soluble or Insoluble in water: Dirt
Varvara68 [4.7K]

Answer:

Insoluble

Explanation:

Like other non-polar molecules such as petrol, wax and grease, most food and dirt is not soluble in water.

https://www.primaryconnections.org.au/sites/all/modules/primaryconnections/includes/SBR/data/Chem/sub/soap/soap.htm#:~:targetText=Like%20other%20non%2Dpolar%20molecules,is%20not%20soluble%20in%20water.

5 0
4 years ago
On the addition of HI
victus00 [196]

Answer:

CH_3-CH(I)-CH(CH_3)-CH_3

I-CH_2-CH_2-CH(CH_3)-CH_3

Explanation:

Given the compound CH_2=CH-CH(CH_3)-CH_3

The steps of reaction:

HI \longrightarrow H^+ + I^-

CH_2=CH-CH(CH_3)-CH_3 + H^+ \longrightarrow CH_3-CH^+-CH(CH_3)-CH_3

<u>But this intermediate product has a resonance: </u>

CH_3-CH^+-CH(CH_3)-CH_3 \longleftrightarrow C^+H_2-CH2-CH(CH_3)-CH_3

The reaction with I-

CH_3-CH^+-CH(CH_3)-CH_3 + I^- \longrightarrow CH_3-CH(I)-CH(CH_3)-CH_3

C^+H_2-CH2-CH(CH_3)-CH_3 + I^- \longrightarrow I-CH_2-CH_2-CH(CH_3)-CH_3

8 0
3 years ago
12 g of powdered magnesium oxide reacts with nitric acid to
galben [10]

Answer:

80.8 g

Explanation:

First, let's write a balanced equation of this reaction

MgO + 2HNO₃ → Mg(NO₃)₂ + H₂O

Now let's convert grams to moles

We gotta find the weight of MgO

24 + 16 = 40 g/mol

12/40 = 0.3 moles of MgO

We can use this to find out how much Magnesium Nitrate will be formed

0.3 x 1 MgO / 1 Mg(NO₃)₂ = 0.3 moles of Magnesium Nitrate formed

Convert moles to grams

Find the weight of Mg(NO₃)₂ but don't forget that 2 subscript acts as a multiplier of whatever is inside that parenthesis.

24 + 14 x 2 + 16 x 3 x 2 = 148 g/mol

148 x 0.3 = 80.8 g

4 0
3 years ago
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