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PSYCHO15rus [73]
3 years ago
8

For the reaction N₂(g) + 3H₂(g) ⇌ 2NH₃(g) what is the value of Kc at 500 ∘C if the equilibrium concentrations are as follows:

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer:

Kc = 70

Explanation:

This is the reaction:

N₂(g) + 3H₂(g) ⇌ 2NH₃(g)

Let's make the expression for K, with concentration at equilibrium and in molarity.

Kc = [NH₃]²  /  [H₂]³ . [N₂]

Kc = (2.1)² / (0.5)³ . 0.5

Kc = 4.41 / 0.0625 → 70

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