Answer:
The answer to your question is:
a) 4.64 x 10 ¹⁵ molecules
b) 9.28 x 10 ¹⁵ atoms of O2
Explanation:
MW C7H14O2 = 84 + 14 + 32 = 130 g
a) 130 g of C7H14O2 ---------------- 1 mol of C7H14O2
1 x 10 ⁻⁶ g --------------- x
x = 7.7 x 10 ⁻⁹ mol
1 mol of C7H14O2 -------------- 6 .023 x 10 ²³ molecules
7.7 x 10⁻⁹ mol -------------- x
x = 4.64 x 10¹⁵ molecules
b) 130 g of C7H14O2 ---------------- 1 mol of C7H14O2
1 x 10⁻⁶ C7H14O2 ----------------- x
x = 7.7 x 10 ⁻⁹ mol of C7H14O2
1 mol of C7H14O2 --------------- 2 mol of O2
7.7 x 10 ⁻⁹ ---------------- x
x = 1.54 x 10⁻⁸ mol of O2
1 mol of O2 ----------------- 6.023 x 10 ²³ atoms
1.54 x 10 ⁻⁸ ---------------- x
x = 9.28 x 10 ¹⁵ atoms of O2
