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4 years ago

Which of the following characteristics describes aerobic organisms.

Chemistry

1 answer:

horsena [70]4 years ago

6 0

Answer: Option (3) is the correct answer.

Explanation:

Aerobic organisms are the organisms which survive and grow in the presence of oxygen.

When oxidation of glucose occurs in the presence of oxygen then it is known as aerobic respiration.

In aerobic respiration, food releases energy to produce ATP which is necessary for cell activity. There is complete breakdown of glucose in aerobic respiration that is why more energy is released. Therefore, aerobic organisms become active.

Thus, we can conclude that characteristics very active, efficient use of energy describes aerobic organisms.

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I need helps plss!!!!

Leni [432]

Answer:

Copper = 2 Boron = 12 (copper and boron combined = 14)

Explanation:

the number after the element is the amount of atoms there is

8 0

3 years ago

Help with this question plz

Triss [41]

Increase, because you need heat to melt a solid to a liquid, so the temperature will have to get greater.

6 0

4 years ago

PLEASE HELP!!!

neonofarm [45]

Answer:

$Cl_2+2NaI\rightarrow I_2+2NaCl$

Explanation:

Hello there!

In this case, according to the described chemical reaction, Cl2 replaces iodine in NaI in order to produce I2 and NaCl:

$Cl_2+NaI\rightarrow I_2+NaCl$

It is possible to realize how chlorine replaces iodine in agreement with the single displacement reaction. Moreover, since chlorine and iodine atoms are not correctly balanced, we add a 2 in front of both NaI and NaCl in order to do so:

$Cl_2+2NaI\rightarrow I_2+2NaCl$

Best regards!

8 0

3 years ago

Determine the [H3O+] in a 0.265 M HClO solution. The Ka of HClO is 2.9 × 10-8.

dexar [7]

8.8 × 10-5 M is the [H3O+] concentration in 0.265 M HClO solution.

Explanation:

HClO is a weak acid and does not completely dissociate in water as ions.

the equation of dissociation can be written and ice table to be formed.

HClO +H2O ⇒ ClO- + H3O+

I 0.265 0 0

C -x +x +x

E 0.265-x +x +x

Now applying the equation of Ka, where Ka is given as 2.9 × 10-8.

Ka = $\frac{[ClO-][H3O+]}{[HClO]}$

2.9 × 10^-8 = $\frac{[x] [x]}{[0.265-x]}$

$x^{2}$ = 7.698 x $10^{-9}$

x = 8.8 × 10-5 M

The hydronium ion concentration is 8.8 × 10-5 M in 0.265 M solution of HClO.

8 0

3 years ago

How many moles of oxygen are needed to react with 87 grams of aluminum

labwork [276]

Answer:

2.4 moles of oxygen are needed to react with 87 g of aluminium.

Explanation:

Chemical equation:

4Al(s) + 3O₂(l) → 2AlO₃(s)

Given data:

Mass of aluminium = 87 g

Moles of oxygen needed = ?

Solution:

Moles of aluminium:

Number of moles of aluminium= Mass/ molar mass

Number of moles of aluminium= 87 g/ 27 g/mol

Number of moles of aluminium= 3.2 mol

Now we will compare the moles of aluminium with oxygen.

Al : O₂

4 : 3

3.2 : 3/4×3.2 = 2.4 mol

2.4 moles of oxygen are needed to react with 87 g of aluminium.

5 0

3 years ago