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Shkiper50 [21]
3 years ago
6

A weather balloon filled with helium has a volume of 700 L at STP. To find the mass of helium which conversion factors would you

use
A) 22.4 L/mol x 4 g/mol
B) 700 L / 4 g/mol
C) (22.4 L/mol / 700 L ) / (4 g/mol)
D) (700 L / 22.4 L/mol) (4 g/mol)
Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
3 0

Answer:

D: (700 L / 22.4 L/mol) (4 g/mol)

Explanation:

At STP, Molar volume of a gas = 22.4 L/mol

Now, we are told that helium has a volume of 700 L at STP.

Also, atomic mass of helium = 4 g/mol

Thus, the mass of helium is given as;

(700 L/22.4 L/mol) × 4 g/mol

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3 of them will be explained.

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5 0
1 year ago
A volume of 25cm3 of a carbonate solution of concentration 0.2mol dm-3 was neutralized by 20 cm3 of acid of concentration 0.5 mo
Galina-37 [17]

Answer: 1 mol of carbonate to 2 mol of acid

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}  

a) \text{Moles of carbonate}=\frac{0.2moldm^{-3}\times 25cm^3}{1000}=0.005mol

b) \text{Moles of acid}=\frac{0.5moldm^{-3}\times 20cm^3}{1000}=0.01mol

Thus the mole ratio of carbonate to acid is = \frac{0.005}{0.01}=\frac{1}{2}

7 0
3 years ago
PLEASE HELP!!
Ray Of Light [21]
So that every measurement is accurate.. hope this helps
7 0
3 years ago
How many moles of oxygen are produced when 26.5 mol of aluminum oxide are decomposed?
spayn [35]
The balanced chemical reaction is written as:

<span>2Al2O3 = 4Al + 3O2

We are given the amount of aluminum oxide used in the reaction. This will be the starting point for the calculations. We do as follows:

26.5 mol Al2O3 ( 3 mol O2 / 2 mol Al2O3 ) = 39.75 mol O2 produced</span>
7 0
3 years ago
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