Answer: Acceleration and velocity
Explanation:
Newton's second law says that when a constant force acts on a massive body, it causes it to accelerate, i.e., to change its velocity, at a constant rate. In the simplest case, a force applied to an object at rest causes it to accelerate in the direction of the force.
Answer is: the partial pressure of the helium gas is 0.158 atm.
p(mixture) = 0.48 atm; total pressure.
m(H₂) = 1.0 g; mass of hydrogen gas.
n(H₂) = m(H₂) ÷ M(H₂).
n(H₂) = 1.0 g ÷ 2 g/mol.
n(H₂) = 0.5 mol; amount of hydrogen.
m(He) = 1.0 g; mass of helium.
n(He) = 1 g ÷ 4 g/mol.
n(He) = 0.25 mol; amount of helium.
χ(H₂) = 0.5 mol ÷ 0.75 mol.
χ(H₂) = 0.67; mole fraction of hydrogen.
χ(He) = 0.25 mol ÷ 0.75 mol.
χ(He) = 0.33; mole fraction of helium.
p(He) = 0.33 · 0.48 atm.
p(He) = 0.158 atm; the partial pressure of the helium gas.
Answer:
In the shell...
Explanation:
In the electronic shell, or the orbit..
Bohr's Atomic Model was given by Niels Bohr. He proposed that the electrons inside an atom moved around in orbits or shells. There were different shells in the atom named as K, L, M, N... These were also called energy levels...
Answer:
I think it's A or D im not sure which one..
<u>Answer:</u> The standard change in Gibbs free energy for the given reaction is 4.33 kJ/mol
<u>Explanation:</u>
For the given chemical equation:
The expression of 
for the given reaction:
We are given:
Putting values in above equation, we get:
To calculate the standard Gibbs free energy, we use the relation:
where,
= standard Gibbs free energy
R = Gas constant = 
T = temperature = ![25^oC=[25+273]K=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B25%2B273%5DK%3D298K)
= equilibrium constant in terms of partial pressure = 0.174
Putting values in above equation, we get:
Hence, the standard change in Gibbs free energy for the given reaction is 4.33 kJ/mol
