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lara [203]
4 years ago
11

The intensity of electromagnetic waves from the sun is 1.4 kW/m2 just above the earth's atmosphere. Eighty percent of this reach

es the surface at noon on a clear summer day. Suppose you model your back as a 25 cm * 52 cm rectangle.How many joules of solar energy fall on your back as you work on your tan for 0.90 h? Answer in Joules.
Physics
1 answer:
Lina20 [59]4 years ago
3 0

Answer:

4.7 × 10⁵J

Explanation:

E = I * a * t

80% = 0.80

25cm = 0.25m

52cm = 0.52m

0.90h = 3240s

E = (0.80)(1400)(0.25 * 0.52)(3240)

= 4.7 * 10⁵J

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It is 5.0 km from your home to the physics lab. As part of your physical fitness program, you could run that distance at 10 km/h
Ostrovityanka [42]

Answer:

Walking burns up more energy,1740000J

Explanation:

Given that the displacement is 5.0km, and running at 10km/h and uses, walking at 3km/hr and uses 290watts:

Energy consumption for running is calculated as:

700watts=700j/s,d=5000m,v=\frac{25}{9}m/s\\\\\therefore E_c=\frac{d}{v}\times Energy \ usage\\\\=\frac{5000}{\frac{25}{9}}\times 700j/s\\\\=1260000J

Energy consumption for walking is calculated as:

290watts=290j/s,d=5000m,v=\frac{5}{6}m/s\\\\\therefore E_c=\frac{d}{v}\times Energy \ usage\\\\=\frac{5000}{\frac{5}{6}}\times 290j/s\\\\=1740000J

Walking is a slower process hence the need for more energy over longer periods  raltive to running the same distance.

Hence walking burns more energy; 1,740,000J. It burns more because you walk for a greater period of time.

5 0
3 years ago
A person is standing on a level floor. His head, upper
BabaBlast [244]

Answer:

y_{cg} = 1.03 m

Explanation:

Given data:

weigh (head+arms + head) w_1 = 438 N

centre of gravity y_1= 1.28 m

weigh (upper leg) w_2 = 144 N

Center of gravity y_2 = 0.760 m

weigh ( lower leg + feet) = 87 N

centre of gravity = y_3 = 0.250 m

location of center of gravity = \frac{w_1 y_1 + w_2 y_2 + w_3 y_3}{w_1 +W_2 +w_3}

y_{cg} = \frac{438 \times 1.28 + 144\times 0.760 + 87 \times 0.250}{438+144+87}

y_{cg} = 1.03 m

8 0
4 years ago
Make the following prefix conversions.<br> 0.001s =ms
Free_Kalibri [48]

Answer:

To convert a millisecond measurement to a second measurement, divide the time by the conversion ratio. The time in seconds is equal to the milliseconds divided by 1,000.

Explanation:

hope it helps

4 0
2 years ago
Sometimes a new experimental result may seem to go against a well-established scientific theory. Which statement BEST describes
MrMuchimi
The best thing to do in this case is to redo the experiment and re record the info, it has to be precise and accurate so you also have to check if your procedure is correct. If the results are both accurate and precise then you have to report your findings to the committee of that specific field. <span />
7 0
3 years ago
Read 2 more answers
If earth had no atmosphere , would a falling object ever reach terminal velocity?
Bas_tet [7]
The right answer is no.
6 0
3 years ago
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