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dusya [7]
3 years ago
13

The hydronium ion concentration in an aqueous solution is [H+] = 5.3 x10-4 M. What is the hydroxide ion concentration? Is this s

olution acidic or basic?
A.) [OH-] = 1.9 x10-11 M, acidic

B.) [OH-] = 4.7 x10-6 M, basic

C.) [OH-] = 1.1 x10-9 M, acidic

D.) [OH-] = 3.2 x10-8 M, acidic
Physics
1 answer:
VladimirAG [237]3 years ago
6 0

Answer:a

Explanation:

Given

[H^+]=5.3\times 10^{-4}\ M

and pH+pOH=14

Also pH=-\log [H^+]

therefore pH=-\log (5.3\times 10^{-3})

pH=-(-4-\log (5.3))

pH=3.275

Thus pOH=14-3.275

pOH=10.275

and pOH=-\log [OH^{-}]

[OH]^{-1}=10^{-10.25}

[OH]^{-1}=1.88\times 10^{-11}\ M

As the pH is less than 7 therefore solution is acidic

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antiseptic1488 [7]

Answer:

Due to equal pressure in all the direction at a particular level in a fluid medium (Pascal's Law)

Explanation:

We are not crushed by the weight of the atmosphere because atmosphere is a fluid and we are immersed into it. So, according to the Pascal's law the the pressure a each point in a horizontal level is equal in all the direction irrespective of the orientation of a body.

Variation of pressure in term of the height of a fluid medium is given as:

P=\rho.g.h

\rho=density of fluid

g = acceleration due to gravity

h = height of the free surface of the fluid from the immersed object.

  • And atmosphere has very less variation of pressure with change in height as it is a rare medium fluid and so for a human height there is very negligible variation of pressure at the heat of a human with respect to his toe.

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3 years ago
A diver stands on a diving platform 10.0 m above the surface of a pool and leaps upward with an initial speed of 2.5 m/s. how fa
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<span>The diver is heading downwards at 12 m/s Ignoring air resistance, the formula for the distance under constant acceleration is d = VT - 0.5AT^2 where V = initial velocity T = time A = acceleration (9.8 m/s^2 on Earth) In this problem, the initial velocity is 2.5 m/s and the target distance will be -7.0 m (3.0 m - 10.0 m = -7.0 m) So let's substitute the known values and solve for T d = VT - 0.5AT^2 -7 = 2.5T - 0.5*9.8T^2 -7 = 2.5T - 4.9T^2 0 = 2.5T - 4.9T^2 + 7 We now have a quadratic equation with A=-4.9, B=2.5, C=7. Using the quadratic formula, find the roots, which are -0.96705 and 1.477251164. Now the diver's velocity will be the initial velocity minus the acceleration due to gravity over the time. So V = 2.5 m/s - 9.8 m/s^2 * 1.477251164 s V = 2.5 m/s - 14.47706141 m/s V = -11.97706141 m/s So the diver is going down at a velocity of 11.98 m/s Now the negative root of -0.967047083 is how much earlier the diver would have had to jump at the location of the diving board. And for grins, let's compute how fast he would have had to jump to end up at the same point. V = 2.5 m/s - 9.8 m/s^2 * (-0.967047083 s) V = 2.5 m/s - (-9.477061409 m/s) V = 2.5 m/s + 9.477061409 m/s V = 11.97706141 m/s And you get the exact same velocity, except it's the opposite sign. In any case, the result needs to be rounded to 2 significant figures which is -12 m/s</span>
7 0
3 years ago
What principle is responsible for alternating light and dark bands when light passes through two or more narrow slits? What prin
kipiarov [429]

Answer:

Interference

Explanation:

When two waves of same frequency and constant phase difference super impose at a point on the screen then due to their superposition we will get different intensity of light at different positions of the screen

This phenomenon of redistribution of energy is known as interference of light.

So at the position of screen where the light intensity is maximum on the screen is known as constructive interference while the positions on the screen where it will get minimum intensity on the screen is known as destructive interference of the light

So correct answer would be

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4 0
3 years ago
a0.155 kg arrow is shot from ground level, upward at 31.4 m/s. what is its kinetic energy (ke) when it is 30.0 m above the groun
swat32

The kinetic energy (KE) of a 0.155 kg arrow that is shot from ground level, upward at 31.4 m/s, when it is 30.0 m above the ground is 30.85 J

Assuming air friction is negligible,

a = - 9.8 m / s²

u = 31.4 m / s

s = 30 m

v² = u² + 2 a s

v² = 31.4² + ( 2 * - 9.8 * 30 )

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KE = 1 / 2 m v²

KE = 1 / 2 * 0.155 * 397.96

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Therefore, the kinetic energy ( KE ) when it is 30.0 m above the ground is 30.85 J

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Mariulka [41]

Answer:

Yes

Explanation:

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p=mv

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And therefore, an ant which is moving (so, non-zero speed) can have more momentum than an elephant, if the elephant is at rest.

6 0
3 years ago
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