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dusya [7]
3 years ago
13

The hydronium ion concentration in an aqueous solution is [H+] = 5.3 x10-4 M. What is the hydroxide ion concentration? Is this s

olution acidic or basic?
A.) [OH-] = 1.9 x10-11 M, acidic

B.) [OH-] = 4.7 x10-6 M, basic

C.) [OH-] = 1.1 x10-9 M, acidic

D.) [OH-] = 3.2 x10-8 M, acidic
Physics
1 answer:
VladimirAG [237]3 years ago
6 0

Answer:a

Explanation:

Given

[H^+]=5.3\times 10^{-4}\ M

and pH+pOH=14

Also pH=-\log [H^+]

therefore pH=-\log (5.3\times 10^{-3})

pH=-(-4-\log (5.3))

pH=3.275

Thus pOH=14-3.275

pOH=10.275

and pOH=-\log [OH^{-}]

[OH]^{-1}=10^{-10.25}

[OH]^{-1}=1.88\times 10^{-11}\ M

As the pH is less than 7 therefore solution is acidic

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When an object moves, stops moving, changes speed, or changes direction, how do scientists describe that condition?
lorasvet [3.4K]
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3 years ago
A slender rod is 90.0 cm long and has mass 0.120 kg. A small 0.0200 kg sphere is welded to one end of the rod, and a small 0.070
likoan [24]

Given Information:

length of slender rod = L = 90 cm = 0.90 m

mass of slender rod = m = 0.120 kg

mass of sphere welded to one end = m₁ = 0.0200 kg

mass of sphere welded to another end = m₂ = 0.0700 kg (typing error in the question it must be 0.0500 kg as given at the end of the question)

Required Information:

Linear speed of the 0.0500 kg sphere = v = ?

Answer:

Linear speed of the 0.0500 kg sphere = 1.55 m/s

Explanation:

The velocity of the sphere can by calculated using

ΔKE = ½Iω²

Where I is the moment of inertia of the whole setup ω is the speed and ΔKE is the change in kinetic energy

The moment of inertia of a rigid rod about center is given by

I = (1/12)mL²

The moment of inertia due to m₁ and m₂ is

I = (m₁+m₂)(L/2)²

L/2 means that the spheres are welded at both ends of slender rod whose length is L.

The overall moment of inertia becomes

I = (1/12)mL² + (m₁+m₂)(L/2)²

I = (1/12)0.120*(0.90)² + (0.0200+0.0500)(0.90/2)²

I = 0.0081 + 0.01417

I = 0.02227 kg.m²

The change in the potential energy is given by

ΔPE = m₁gh₁ + m₂gh₂

Where h₁ and h₂ are half of the length of slender rod

L/2 = 0.90/2 = 0.45 m

ΔPE = 0.0200*9.8*0.45 + 0.0500*9.8*-0.45

The negative sign is due to the fact that that m₂ is heavy and it would fall and the other sphere m₁ is lighter and it would will rise.

ΔPE = -0.1323 J

This potential energy is then converted into kinetic energy therefore,

ΔKE = ½Iω²

0.1323 = ½(0.02227)ω²

ω² = (2*0.1323)/0.02227

ω = √(2*0.1323)/0.02227

ω = 3.45 rad/s

The linear speed is

v = (L/2)ω

v = (0.90/2)*3.45

v = 1.55 m/s

Therefore, the linear speed of the 0.0500 kg sphere as its passes through its lowest point is 1.55 m/s.

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