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2 years ago

11

A 18-g paper clip is attached to the rim of a phonograph record with a diameter of 48 cm, spinning at 3.2 rad/s. What is the mag

nitude of its angular momentum (in kg m2/s)? Round your answer to the nearest ten-thousandth.

1 answer:

Artist 52 [7]2 years ago

5 0

Answer:

Magnitude of its angular momentum = 0.0017 kgm²/s

Explanation:

Angular momentum, L = Iω

I is mass moment of inertia and ω is angular velocity.

Phonograph is in disc shape,

$\texttt{I for disc =}\frac{MR^2}{2}$

Radius = 0.5 x 48 = 24 cm = 0.24 m

Angular velocity, ω = 3.2 rad/s

Mass, M = 18 g = 0.018 kg

Substituting

$L=\frac{0.018\times 0.24^2}{2}\times 3.2 =0.0017kgm^2/s$

Magnitude of its angular momentum = 0.0017 kgm²/s

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The length of an aluminum wire is quadrupled and the radius is doubled. By which factor does the resistance change?

erik [133]

The resistance of a conductive wire is given by:
$R= \frac{\rho L}{A}$
where
$\rho$ is the material resistivity
$L$ is the wire length
$A$ is the cross-sectional area of the wire

The length of the wire is quadrupled, so if we call L the original length and L' the new length, we can write
$L'=4 L$

Similarly, the radius of the wire is doubled (r'=2r), so the new area is
$A'= \pi (r')^2 = \pi (2r)^2 = 4 \pi r^2 = 4A$

And if we substitute into the equation, we find that the new resistance of the wire is
$R'= \frac{\rho L'}{A'}= \frac{\rho (4L)}{4 A'} = \frac{\rho L}{A}=R$
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2 years ago

Write your question here (Keep it simple and clear to get the best answer) a car accelerates uniformly from an initial velocity

Fittoniya [83]

Answer:

Average velocity = 18 m/s

Explanation:

Given the following data;

Initial velocity = 10m/s

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Time = 4 seconds

To find the average velocity, we would use the first equation of motion;

$V = U + at$

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting into the equation, we have;

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2 years ago

A student pushed a box 32.0 m across a smooth, horizontal floor using a constant force of 124 N. If the force was applied for 8.

Brilliant_brown [7]

The power developed is 500 W ( to the nearest Watt)

Power(P) is the rate at which work is done. Work done (W) is the product of the force applied on the object and the displacement (s) made by the point of application of the force.

$P = \frac{W}{t}$

$W= F*s$

Therefore,

$P=\frac{F*s}{t}$

Substitute the given values of force , displacement and time

$F = 124 N,s = 32.0 m,t = 8.0 s$

$P =\frac{W*s}{t} =\frac{124N*22.0s}{8.0s} =496 W$

Thus the Power can be rounded off to the nearest value of 500 W

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3 years ago

Read 2 more answers

What is the magnitude and direction (right or left) of the

Sunny_sXe [5.5K]

Answer: 12 N to the right

Explanation:

If we calculate the net force acting on the box, we will have:

<u>In y-component:</u>

$Fy_{net}=F_{n}+F_{g}$ (1)

Where $F_{n}=12 N$ is the Normal force, directed upwards and $F_{g}=-12 N$ is the weight of the box (gravity force), directed downwards.

$Fy_{net}=12 N-12 N$ (2)

$Fy_{net}=0 N$ (3) Hence the net force in the vertical component is zero

<u>In x-component:</u>

$Fx_{net}=F_{left}+F_{right}$ (4)

Where $F_{left}=-3 N$ and $F_{right}= 15 N$

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$Fx_{net}=12 N$ (6) This is the net force in the horizontal component

Therefore, the total net force acting on the box is 12 N directed to the right

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2 years ago

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CaHeK987 [17]

To solve the problem it is necessary to apply the concepts related to Byle's Law and Avogadro's Law.

The ideal gas equation would help us find the final solution to the problem, defined by

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R = Universal as constant

n = number of moles

V = Volume

P = Pressure

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$[tex]Zn = \frac{2.2}{65}$ [/tex]

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Applying the previous equation we have that

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3 years ago