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adoni [48]
3 years ago
11

What test were used to find out information about the iceman

Physics
1 answer:
Blababa [14]3 years ago
6 0
To find information, the would take DNA tests.
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BRAINLIEST AND MAY DOUBLE POINTS!!!
raketka [301]

Given that:

 Energy of bulb  (Work ) = 30 J,

 Time (t) = 3 sec

The power consumption =  ?

 We know that, Power can be defined as rate of doing work

              Power (P) = Work(Energy supplied) ÷ time

                               = 30 ÷ 3

                              = 10 Watts

<em> The power consumption is 10 W.</em>


3 0
3 years ago
What are the units for the spring constant, k?
Mnenie [13.5K]

C. newtons/meter

Explanation:

The unit of spring constant K is newtons/meter.

The spring constant is also known as the stiffness.

    F = k e

F is the force

k is the spring constant

e is the extension.

 The unit of F is newtons

                    e is meters

Therefore, k becomes newtons/meter

  • Stiffness is the resistance to stretch of a body.

learn more:

Force brainly.com/question/3820012

#learnwithBrainly

4 0
3 years ago
An athlete at high performance inhales 4.0L of air at 1 atm and 298 K. The inhaled and exhaled air contain 0.5% and 6.2% by volu
LenaWriter [7]

To solve this problem we will calculate the total volume of inhaled and exhaled water. From the ideal gas equation we will find the total number of moles of water.

An athlete at high performance inhales 4.0L of air at 1atm and 298K.

The inhaled and exhaled air contain 0.5% and 6.2% by volume of water, respectively.

During inhalation, volume of water taken is

V_i = (4L)(0.5\%)

V_i = 0.02L

During exhalation, volume of water expelled is

V_e = (4L)(6.2\%)

V_e = 0.248L

During 40 breathes, total volume of water taken is

V_{it} = (40L)(0.02L) = 0.8L

During 40 breathes, total volume of water expelled out is

V_{et} = (40L)(0.248L) = 9.92L

Therefore resultant volume of water expelled out from the lung is

\Delta V = 9.92L-0.8L = 9.12

From the body through the lung we have that

n = \frac{PV}{RT}

Here,

P = Pressure

R= Gas ideal constant

T= Temperature

V = Volume

Replacing,

n = \frac{(1atm)(9.12L)}{(8.314J/mol \cdot K)(298K)}

n = 0.373mol/min

Therefore the moles of water per minute are expelled from the body through the lungs is 0.373mol/min

8 0
3 years ago
B. hammer
andrew11 [14]

we can’t andwer u need to include a answer

Explanation:

4 0
3 years ago
A 0.950 kg block is attached to a spring with spring constant 16 N/m . While the block is sitting at rest, a student hits it wit
3241004551 [841]

Answer:

A)0.1m

B)vf= 35cm/s

Explanation:

7 0
2 years ago
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